No, a StringBuilder is a purely managed resource. You should just get rid of all references to it. Everything else is taken care of by the garbage collector: StringBuilder sb = …; // … do work sb = null; // or simply let it go out of scope. In .NET, there’s no deterministic delete (like … Read more
To replace [… chars] and [truncated]… with actual characters (no matter how long, and no matter what the type of the compared values are), add this to your *_test.py file: if ‘unittest.util’ in __import__(‘sys’).modules: # Show full diff in self.assertEqual. __import__(‘sys’).modules[‘unittest.util’]._MAX_LENGTH = 999999999 Indeed, as other answers have noted, setting self.maxDiff = None doesn’t help, … Read more
The designers of this feature realized this requirement as well (see ‘New escape sequences’ in JEP368). So, with the latest early access build for JDK 14 you can use a trailing \ to escape the new line at the end of a line: public class Main { public static void main(String[] args) { String paragraph … Read more
Possible solutions to codepoint slicing I know I can use the chars() iterator and manually walk through the desired substring, but is there a more concise way? If you know the exact byte indices, you can slice a string: let text = “Hello привет”; println!(“{}”, &text[2..10]); This prints “llo пр”. So the problem is to … Read more
There is no standard library function to do this, but it’s not too hard to roll your own. There is an existing question on SO about doing this that was answered with source code.
You have to convert the string to UTF-8 data first let string = “foo bar” let data = string.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)! and then write it to the output stream let outputStream: NSOutputStream = … // the stream that you want to write to let bytesWritten = outputStream.write(UnsafePointer(data.bytes), maxLength: data.length) The UnsafePointer() cast is necessary because … Read more
Try std::stoull if you are using C++11 or greater. This post may also be of help. I didnt mark this as a duplicate because the other question is about C.
Another solution (not that pythonic, but very fast) is to use string.translate – though note that this will not work for unicode. It’s also worth noting that you can speed up Dana’s code by moving the characters into a set (which looks up by hash, rather than performing a linear search each time). Here are … Read more
If you’re trying to do this in ipython notebook, you can do: from IPython.display import display, HTML def pretty_print(df): return display( HTML( df.to_html().replace(“\\n”,”<br>”) ) )