String concatenation using preprocessor
Concatenation of adjacent string litterals isn’t a feature of the preprocessor, it is a feature of the core languages (both C and C++). You could write: printf(“Hello ” ” world\n”);
Concatenation of adjacent string litterals isn’t a feature of the preprocessor, it is a feature of the core languages (both C and C++). You could write: printf(“Hello ” ” world\n”);
char *test = (char*) malloc(12*sizeof(char)); +-+-+-+-+-+-+-+-+-+-+-+-+ test—>|x|x|x|x|x|x|x|x|x|x|x|x| (uninitialized memory, heap) +-+-+-+-+-+-+-+-+-+-+-+-+ test = “testingonly”; +-+-+-+-+-+-+-+-+-+-+-+-+ test + |x|x|x|x|x|x|x|x|x|x|x|x| | +-+-+-+-+-+-+-+-+-+-+-+-+ | +-+-+-+-+-+-+-+-+-+-+-+-+ +->|t|e|s|t|i|n|g|o|n|l|y|0| +-+-+-+-+-+-+-+-+-+-+-+-+ free(test); // error, because test is no longer pointing to allocated space. Instead of changing the pointer test, you need to copy the string “testingonly” into the allocated place using e.g. … Read more
Using Pandas str.replace and regex: df[“new_column”] = df[‘review’].str.replace(‘[^\w\s]’,”)
Apache Commons Lang contains a StringUtils.join() method for precisely this purpose. Note that different flavours exist. And as of March 2014, Java 8 now has a StringJoiner
Another option could be to use an implicit operator. Example: class Foo { readonly string _value; public Foo(string value) { this._value = value; } public static implicit operator string(Foo d) { return d._value; } public static implicit operator Foo(string d) { return new Foo(d); } } The Foo class acts like a string. class Example … Read more
A quick one line would be: B = A?.Length > 40 ? A.Substring(0, 40) : A; which only implements the substring when the length is more than 40. For the sake of redundancy, 40 would preferably be a variable of course. The use of ‘?.’ prevents errors when ‘A’ is null. As ean5533 mentioned A.Substring(0, … Read more
You can use multiple lines string representation in JavaScript: JSON.parse(‘{“a” : “a\ asd”}’) Tried in console. It works.
Read up on the Aho-Corasick algorithm and the Rabin-Karp algorithm. If the input is not too large, you don’t want to repeat the search many times and you do not have many patterns, it might be a good idea to use a single pattern algorithm several times. The Wikipedia article on search algorithms gives many … Read more
You can just use the “@Size”-annotation twice: @Size(min = 2, message = “{validation.name.size.too_short}”) @Size(max = 200, message = “{validation.name.size.too_long}”) private String name;