A sorting algorithm is said to be stable if two objects with equal keys appear in the same order in sorted output as they appear in the input array to be sorted. Some sorting algorithms are stable by nature like Insertion sort, Merge Sort, Bubble Sort, etc. And some sorting algorithms are not, like Heap … Read more
For any optimization, it’s always best to test, test, test. I would try at least sorting networks and insertion sort. If I were betting, I’d put my money on insertion sort based on past experience. Do you know anything about the input data? Some algorithms will perform better with certain kinds of data. For example, … Read more
This will give you a sorted version of the array. sorted(timestamps, reverse=True) If you want to sort in-place: timestamps.sort(reverse=True) Check the docs at Sorting HOW TO
Reserved.objects.filter(client=client_id).order_by(‘-check_in’) Notice the – before check_in. Django Documentation
As of the 0.17.0 release, the sort method was deprecated in favor of sort_values. sort was completely removed in the 0.20.0 release. The arguments (and results) remain the same: df.sort_values([‘a’, ‘b’], ascending=[True, False]) You can use the ascending argument of sort: df.sort([‘a’, ‘b’], ascending=[True, False]) For example: In [11]: df1 = pd.DataFrame(np.random.randint(1, 5, (10,2)), columns=[‘a’,’b’]) … Read more
Collections.sort(testList); Collections.reverse(testList); That will do what you want. Remember to import Collections though! Here is the documentation for Collections.
ES6 using rest parameters If you are able to use ES6 you can use: Rest Parameters function sortArgs(…args) { return args.sort(function (a, b) { return a – b; }); } document.body.innerHTML = sortArgs(12, 4, 6, 8).toString(); As you can read in the link The rest parameter syntax allows us to represent an indefinite number of … Read more
Basic answer: mylist = [“b”, “C”, “A”] mylist.sort() This modifies your original list (i.e. sorts in-place). To get a sorted copy of the list, without changing the original, use the sorted() function: for x in sorted(mylist): print x However, the examples above are a bit naive, because they don’t take locale into account, and perform … Read more
To sort by the second column of a: a[a[:, 1].argsort()]
If you mean an in-place sort (i.e. the list is updated): people.Sort((x, y) => string.Compare(x.LastName, y.LastName)); If you mean a new list: var newList = people.OrderBy(x=>x.LastName).ToList(); // ToList optional