Use sort_values to sort the df by a specific column’s values: In [18]: df.sort_values(‘2’) Out[18]: 0 1 2 4 85.6 January 1.0 3 95.5 February 2.0 7 104.8 March 3.0 0 354.7 April 4.0 8 283.5 May 5.0 6 238.7 June 6.0 5 152.0 July 7.0 1 55.4 August 8.0 11 212.7 September 9.0 10 … Read more
Shortest Code [x for _, x in sorted(zip(Y, X))] Example: X = [“a”, “b”, “c”, “d”, “e”, “f”, “g”, “h”, “i”] Y = [ 0, 1, 1, 0, 1, 2, 2, 0, 1] Z = [x for _,x in sorted(zip(Y,X))] print(Z) # [“a”, “d”, “h”, “b”, “c”, “e”, “i”, “f”, “g”] Generally Speaking [x for … Read more
You are right, the function you’re looking for is array_multisort(). Here’s an example taken straight from the manual and adapted to your case: $price = array(); foreach ($inventory as $key => $row) { $price[$key] = $row[‘price’]; } array_multisort($price, SORT_DESC, $inventory); As of PHP 5.5.0 you can use array_column() instead of that foreach: $price = array_column($inventory, … Read more
List iterators guarantee first and foremost that you get the list’s elements in the internal order of the list (aka. insertion order). More specifically it is in the order you’ve inserted the elements or on how you’ve manipulated the list. Sorting can be seen as a manipulation of the data structure, and there are several … Read more
First, declare your Array as a typed array so that you can call methods when you iterate: var images : [imageFile] = [] Then you can simply do: Swift 2 images.sorted({ $0.fileID > $1.fileID }) Swift 3+ images.sorted(by: { $0.fileID > $1.fileID }) The example above gives the results in descending order.
Use usort, here’s an example adapted from the manual: function cmp($a, $b) { return strcmp($a->name, $b->name); } usort($your_data, “cmp”); You can also use any callable as the second argument. Here are some examples: Using anonymous functions (from PHP 5.3) usort($your_data, function($a, $b) {return strcmp($a->name, $b->name);}); From inside a class usort($your_data, array($this, “cmp”)); // “cmp” should … Read more
A key can be a function that returns a tuple: s = sorted(s, key = lambda x: (x[1], x[2])) Or you can achieve the same using itemgetter (which is faster and avoids a Python function call): import operator s = sorted(s, key = operator.itemgetter(1, 2)) And notice that here you can use sort instead of … Read more
There is one rather sneaky trick not mentioned here so far. We assume that you have no extra way to store data, but that is not strictly true. One way around your problem is to do the following horrible thing, which should not be attempted by anyone under any circumstances: Use the network traffic to … Read more
The other answers to this question are outdated, never matched implementation reality, and have officially become incorrect now that the ES6 / ES2015 spec has been published. See the section on property iteration order in Exploring ES6 by Axel Rauschmayer: All methods that iterate over property keys do so in the same order: First all … Read more
sorted_by_second = sorted(data, key=lambda tup: tup[1]) or: data.sort(key=lambda tup: tup[1]) # sorts in place The default sort mode is ascending. To sort in descending order use the option reverse=True: sorted_by_second = sorted(data, key=lambda tup: tup[1], reverse=True) or: data.sort(key=lambda tup: tup[1], reverse=True) # sorts in place