Let me restart for the third time. We are trying to accelerate q = x / y where y is an integer constant, and q, x, and y are all IEEE 754-2008 binary32 floating-point values. Below, fmaf(a,b,c) indicates a fused multiply-add a * b + c using binary32 values. The naive algorithm is via a … Read more
n % x == 0 Means that n can be divided by x. So… for instance, in your case: boolean isDivisibleBy20 = number % 20 == 0; Also, if you want to check whether a number is even or odd (whether it is divisible by 2 or not), you can use a bitwise operator: boolean … Read more
Just cast the resulting value to an int. $n = (int) ($i / $m); Interesting functions (depending on what you want to achieve and if you expect negative integers to get devided) are floor(), ceil() and round().
CPU’s ALU (Arithmetic-Logic Unit) executes algorithms, though they are implemented in hardware. Classic multiplications algorithms includes Wallace tree and Dadda tree. More information is available here. More sophisticated techniques are available in newer processors. Generally, processors strive to parallelize bit-pairs operations in order the minimize the clock cycles required. Multiplication algorithms can be parallelized quite … Read more
The typical way is to shift and subtract. This is basically pretty similar to long division as we learned it in school. The big difference is that in decimal division you need to estimate the next digit of the result. In binary, that’s trivial. The next digit is always either 0 or 1. If the … Read more
Check if the denominator is zero before dividing. This avoids the overhead of catching the exception, which may be more efficient if you expect to be dividing by zero a lot. def weird_division(n, d): return n / d if d else 0
For the actual values, i.e. 8.0/(-7.0), the result is roughly -1.143. Your result using integer division is being rounded down toward the more negative value of -2. (This is also known as “Floor division”) This is why you will get the somewhat perplexing answers of: >>> 8/(-7) -2 >>> 8/7 1 Note: This is “fixed” … Read more
Build bipartite graph structure – connect a[i] with all its divisors from b[]. Then find maximum matching and check whether it is perfect matching (number of edges in matching is equal to the number of pairs (if graph is directed) or to doubled number). Arbitrary chosen Kuhn algorithm implementation here. Upd: @Eric Duminil made great … Read more
Make one of those numbers a float. 737/parseFloat(1070) or a bit faster: 737*1.0/1070 convert to 2 decimal places Math.round(737 * 100.0 / 1070) / 100
When you look at the IL-code that those two snippets produce, you’ll realize that VB.NET first converts the integer values to doubles, applies the division and then rounds the result before it’s converted back to int32 and stored in y. C# does none of that. VB.NET IL Code: IL_0000: ldc.i4.s 10 IL_0002: stloc.1 IL_0003: ldc.i4.s … Read more