Found the answer in the different post on here. It was not the accepted answer which it should be Spring RestTemplate with paginated API the answer by @rvheddeg is correct. You just need to put @JsonCreator and provide a constructor with all the properties, here is my RestResponsePage class that fixes the issue. class RestResponsePage<T> … Read more
Jackson processes @JsonTypeInfo before choosing which Deserializer to use, probably because the choice of Deserializer could depend generally on the type. However, you can easily disable this on a per-field basis the same way you specify custom Deserializer – by annotating the field directly: @JsonDeserialize(using = DefinitionDeserializer.class) @JsonTypeInfo(use = JsonTypeInfo.Id.NONE) private Definition definition;
I think it’s likely you’ll need to deserialize the Json then construct the objects from there. Deserializing directly to Cat or Dog won’t be possible as the deserializer won’t know how to construct these objects specifically. Edit: borrowing heavily from Deserializing heterogenous JSON array into covariant List<> using JSON.NET Something like this would work: interface … Read more
If you don’t want to extend DefaultPrettyPrinter you can also just set the indentArraysWith property externally: ObjectMapper objectMapper = new ObjectMapper(); objectMapper.enable(SerializationFeature.INDENT_OUTPUT); DefaultPrettyPrinter prettyPrinter = new DefaultPrettyPrinter(); prettyPrinter.indentArraysWith(DefaultIndenter.SYSTEM_LINEFEED_INSTANCE); String json = objectMapper.writer(prettyPrinter).writeValueAsString(object);
Short answer: @JsonIgnoreProperties(ignoreUnknown=true) is applicable at deserialization of JSON to Java object (POJO) only. If your POJO does not contain certain properties that JSON does contain, they are ignored and no error is thrown. On the other hand @JsonInclude(Include.NON_EMPTY) is used at serialization of POJO to JSON and it says, skip POJO properties that are: … Read more
Why not use python pickle? Python has a great serializing module called pickle it is very easy to use. import cPickle cPickle.dump(obj, open(‘save.p’, ‘wb’)) obj = cPickle.load(open(‘save.p’, ‘rb’)) There are two disadvantages with pickle: It’s not secure against erroneous or maliciously constructed data. Never unpickle data received from an untrusted or unauthenticated source. The format … Read more
In this case you need to annotate the relationships with @JsonManagedReference and @JsonBackReference like this: @ManyToOne @JoinColumn(name = “company_id”, referencedColumnName = “id”) @JsonBackReference private Company company And @OneToMany(mappedBy=”company”) @JsonManagedReference private Set<Employee> employee = new HashSet<Employee>(); There is a nice example here
The simplest way is deserialize array of key-value pairs to IDictionary<string, string>: public class SomeData { public string Id { get; set; } public IEnumerable<IDictionary<string, string>> Data { get; set; } } private static void Main(string[] args) { var json = “{ \”id\”: \”123\”, \”data\”: [ { \”key1\”: \”val1\” }, { \”key2\” : \”val2\” } … Read more
Found a right way how to correctly read the nested JSON object inside the JsonConverter. The complete solution is the following: public class SomeModel { public int Id { get; set; } public string Name { get; set; } [JsonConverter(typeof(InfoToStringConverter))] public string Info { get; set; } } public class InfoToStringConverter : JsonConverter<string> { public … Read more
Assuming you’re using the Newtonsoft.Json.Linq.JObject, you don’t need to use dynamic. The JObject class can take a string indexer, just like a dictionary: JObject myResult = GetMyResult(); returnObject.Id = myResult[“string here”][“id”]; Hope this helps!