Taken from the docs: Gson supports some pre-defined field naming policies to convert the standard Java field names (i.e. camel cased names starting with lower case — “sampleFieldNameInJava”) to a Json field name (i.e. sample_field_name_in_java or SampleFieldNameInJava). See the FieldNamingPolicy class for information on the pre-defined naming policies. It also has an annotation based strategy … Read more
Check out @JsonValue annotation. EDIT: like this: class ItemType { @JsonValue public String name; public int somethingElse; }
I’ve done some test using a Pickled object, lzma gave the best compression. But your results can vary based on your data, I’d recommend testing them with some sample data of your own. Mode LastWriteTime Length Name —- ————- —— —- -a—- 9/17/2019 10:05 PM 23869925 no_compression.pickle -a—- 9/17/2019 10:06 PM 6050027 gzip_test.gz -a—- 9/17/2019 … Read more
In your View Set you may specify the queryset like follows: from rest_framework import serializers, viewsets class MyModelSerializer(serializers.ModelSerializer): class Meta: model = MyModel class MyModelViewSet(viewsets.ModelViewSet): queryset = MyModel.objects.all()[:500] serializer_class = MyModelSerializer I think what you are looking for is the SerializerMethodField. So your code would look as follows: class ContainerSerializer(serializers.ModelSerializer): items = SerializerMethodField(‘get_items’) class Meta: … Read more
You can pass a class to serialize: class User < ActiveRecord::Base serialize :recent_messages, Array end The above ensures that recent_messages is an Array: User.new #=> #<User id: nil, recent_messages: [], created_at: nil, updated_at: nil> Note that you might have to convert existing fields if the types don’t match.
Solution was to add .configure(DeserializationFeature.READ_DATE_TIMESTAMPS_AS_NANOSECONDS, false) to the ObjectMapper. Complete ObjectMapper looks like: ObjectMapper om = new ObjectMapper() .registerModule(new JavaTimeModule()) .configure(SerializationFeature.WRITE_DATE_TIMESTAMPS_AS_NANOSECONDS, false) .configure(SerializationFeature.FAIL_ON_EMPTY_BEANS, false) .configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false) .configure(DeserializationFeature.READ_DATE_TIMESTAMPS_AS_NANOSECONDS, false) .setSerializationInclusion(Include.NON_NULL);
Base implementation, without custom properties SerializableExceptionWithoutCustomProperties.cs: namespace SerializableExceptions { using System; using System.Runtime.Serialization; [Serializable] // Important: This attribute is NOT inherited from Exception, and MUST be specified // otherwise serialization will fail with a SerializationException stating that // “Type X in Assembly Y is not marked as serializable.” public class SerializableExceptionWithoutCustomProperties : Exception { public … Read more
Change your statement var formData = JSON.parse($(“#floorplan-form”).serializeArray()); with var formData = JSON.stringify(jQuery(‘#frm’).serializeArray()); // store json string or var formData = JSON.parse(JSON.stringify(jQuery(‘#frm’).serializeArray())) // store json object
By adding the jackson annotation @JsonTypeInfo in class level you can have the expected output. i just added no-changes in your class. package com.test.jackson; import org.codehaus.jackson.map.ObjectMapper; import org.codehaus.jackson.map.SerializationConfig; import com.fasterxml.jackson.annotation.JsonTypeInfo; import com.fasterxml.jackson.annotation.JsonTypeInfo.As; import com.fasterxml.jackson.annotation.JsonTypeInfo.Id; @JsonTypeInfo(include=As.WRAPPER_OBJECT, use=Id.NAME) public class MyPojo { // Remain same as you have } output: { “MyPojo”: { “id”: 4 } }
Just to check, have you marked Bar as [Serializable]? Also, you need a parameter-less ctor on Bar, to deserialize Hmm, I used: public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { Foo f = new Foo(); f.BarList = new List<Bar>(); f.BarList.Add(new Bar { Property1 = … Read more