Everything is returned correctly. puts 8/3.ceil == 2 #=> true, because 8/3 returns an Integer, 2 puts 8/3.floor == 2 #=> true, because 8/3 returns an Integer, 2 puts 2.67.ceil == 2 #=> false, because 2.67.ceil is 3 puts 2.67.floor == 2 #=> true, because 2.67.floor is 2 To make things of more sense here, … Read more
To round a double up to 2 decimal places, you can use: #include <iostream> #include <cmath> int main() { double value = 0.123; value = std::ceil(value * 100.0) / 100.0; std::cout << value << std::endl; // prints 0.13 return 0; } To round up to n decimal places, you can use: double round_up(double value, int … Read more
Since you’re looking for fourths (.00, .25, .50, .75), multiply your number by 4, round to nearest whole number as desired (floor if down, ceil if up), then divide by 4. 1.32, down to nearest fourth: 1.32 * 4 = 5.28 floor(5.28) = 5.00 5.00 / 4 = 1.25 Same principle applies for any other … Read more
The java.time API does not support rounding to ceiling, however it does support rounding to floor (truncation) which enables the desired behaviour (which isn’t exactly rounding to ceiling): LocalDateTime now = LocalDateTime.now(); LocalDateTime roundFloor = now.truncatedTo(ChronoUnit.MINUTES); LocalDateTime roundCeiling = now.truncatedTo(ChronoUnit.MINUTES).plusMinutes(1); In addition, there is a facility to obtain a clock that only ticks once a … Read more
Check out http://www.php.net/manual/en/function.round.php <?php echo round(3.6451895227869, 2); ?> EDIT Try using this custom function http://www.php.net/manual/en/function.round.php#102641 <?php function round_up ( $value, $precision ) { $pow = pow ( 10, $precision ); return ( ceil ( $pow * $value ) + ceil ( $pow * $value – ceil ( $pow * $value ) ) ) / $pow; … Read more
double has a greater value range than int: The Double value type represents a double-precision 64-bit number with values ranging from negative 1.79769313486232e308 to positive 1.79769313486232e308, as well as positive or negative zero, PositiveInfinity, NegativeInfinity, and Not-a-Number (NaN). Double complies with the IEC 60559:1989 (IEEE 754) standard for binary floating-point arithmetic. That standard says that … Read more
You can use math.ceil with math.log10 to do this: >>> 10 ** math.ceil(math.log10(0.04)) 0.1 >>> 10 ** math.ceil(math.log10(0.7)) 1 >>> 10 ** math.ceil(math.log10(1.1)) 10 >>> 10 ** math.ceil(math.log10(90)) 100 log10(n) gives you the solution x that satisfies 10 ** x == n, so if you round up x it gives you the exponent for the … Read more
Why use external script languages? You get floor by default. To get ceil, do $ divide=8; by=3; (( result=(divide+by-1)/by )); echo $result 3 $ divide=9; by=3; (( result=(divide+by-1)/by )); echo $result 3 $ divide=10; by=3; (( result=(divide+by-1)/by )); echo $result 4 $ divide=11; by=3; (( result=(divide+by-1)/by )); echo $result 4 $ divide=12; by=3; (( result=(divide+by-1)/by … Read more
The range of double is greater than that of long. For example: double x = Long.MAX_VALUE; x = x * 1000; x = Math.ceil(x); What would you expect the last line to do if Math.ceil returned long? Note that at very large values (positive or negative) the numbers end up being distributed very sparsely – … Read more