Python round to next highest power of 10

You can use math.ceil with math.log10 to do this:

>>> 10 ** math.ceil(math.log10(0.04))
0.1
>>> 10 ** math.ceil(math.log10(0.7))
1
>>> 10 ** math.ceil(math.log10(1.1))
10
>>> 10 ** math.ceil(math.log10(90))
100

log10(n) gives you the solution x that satisfies 10 ** x == n, so if you round up x it gives you the exponent for the next highest power of 10.

Note that for a value n where x is already an integer, the “next highest power of 10” will be n:

>>> 10 ** math.ceil(math.log10(0.1))
0.1
>>> 10 ** math.ceil(math.log10(1))
1
>>> 10 ** math.ceil(math.log10(10))
10