(It is probably a bit late for the OP, but it might still be useful for others) Unfortunately Java does not support arrays with more than 231−1 elements. The maximum consumption is 2 GiB of space for a byte[] array, or 16 GiB of space for a long[] array. While it is probably not applicable … Read more
Since Kotlin v1.1 you can use: “ED05265A”.toLong(radix = 16) Until then use the Java’s Long.parseLong.
Better option is use SQLQuery#addScalar than casting to Long or BigDecimal. Here is modified query that returns count column as Long Query query = session .createSQLQuery(“SELECT COUNT(*) as count FROM SpyPath WHERE DATE(time)>=DATE_SUB(CURDATE(),INTERVAL 6 DAY) GROUP BY DATE(time) ORDER BY time;”) .addScalar(“count”, LongType.INSTANCE); Then List<Long> result = query.list(); //No ClassCastException here Related link Hibernate javadocs … Read more
long is Int64 in .NET; it is just an alias in C#. Your problem is casting the return value to long and unless we know the type coming back from your query for sure, we would not know why you get an error. SQL BigInt must be convertable to long. If it is the COUNT(*) … Read more
In Java 8, unsigned long support was introduced. Still, these are typical longs, but the sign doesn’t affect adding and subtracting. For dividing and comparing, you have dedicated methods in Long. Also, you can do the following: long l1 = Long.parseUnsignedLong(“12345678901234567890”); String l1Str = Long.toUnsignedString(l1) BigInteger is a bit different. It can keep huge numbers. … Read more
== compares references, .equals() compares values. These two Longs are objects, therefore object references are compared when using == operator. However, note that in Long id1 = 123L; literal value 123L will be auto-boxed into a Long object using Long.valueOf(String), and internally, this process will use a LongCache which has a [-128,127] range, and 123 … Read more
This should do the trick. (It’s an extension method so that you can call it just as you call the normal Next or NextDouble methods on a Random object). public static Int64 NextInt64(this Random rnd) { var buffer = new byte[sizeof(Int64)]; rnd.NextBytes(buffer); return BitConverter.ToInt64(buffer, 0); } Just replace Int64 with UInt64 everywhere if you want … Read more
No practical difference. Either L or l can be used, both indicate a long primitive. Also, either can be autoboxed to the corresponding Long wrapper type. However, it is worth noting that JLS-3.10.1 – Integer Literals says (in part) An integer literal is of type long if it is suffixed with an ASCII letter L … Read more
The constructor is doing that: Timestamp(long time)
Add L to the end of the number: long bytes = 4294967296L;