math.MaxUint64 is a constant, not an int64. Try instead: fmt.Printf(“%d”, uint64(num)) The issue here is that the constant is untyped. The constant will assume a type depending on the context in which it is used. In this case, it is being used as an interface{} so the compiler has no way of knowing what concrete … Read more
long is Int64 in .NET; it is just an alias in C#. Your problem is casting the return value to long and unless we know the type coming back from your query for sure, we would not know why you get an error. SQL BigInt must be convertable to long. If it is the COUNT(*) … Read more
This should do the trick. (It’s an extension method so that you can call it just as you call the normal Next or NextDouble methods on a Random object). public static Int64 NextInt64(this Random rnd) { var buffer = new byte[sizeof(Int64)]; rnd.NextBytes(buffer); return BitConverter.ToInt64(buffer, 0); } Just replace Int64 with UInt64 everywhere if you want … Read more
You can cast generally using: tf.cast(my_tensor, tf.float32) Replace tf.float32 with your desired type. Edit: It seems at the moment at least, that tf.cast won’t cast to an unsigned dtype (e.g. tf.uint8). To work around this, you can cast to the signed equivalent and used tf.bitcast to get all the way. e.g. tf.bitcast(tf.cast(my_tensor, tf.int8), tf.uint8)
Yes, the answer will be the same on a 64-bit machine. In .NET, an int is a signed 32-bit integer, regardless of the processor. Its .NET framework type is System.Int32. The C# Language specification states: The int type represents signed 32-bit integers with values between –2,147,483,648 and 2,147,483,647.
The types long long and unsigned long long are standard C and standard C++ types each with at least 64 bits. All compilers I’m aware of provide these types, except possibly when in a -pedantic mode but in this case int64_t or uint64_t won’t be available with pre-C++ 2011 compilers, either. On all of the … Read more
You convert them with a type “conversion” var a int var b int64 int64(a) < b When comparing values, you always want to convert the smaller type to the larger. Converting the other way will possibly truncate the value: var x int32 = 0 var y int64 = math.MaxInt32 + 1 // y == 2147483648 … Read more
Not with built-in JSON.parse. You’ll need to parse it manually and treat values as string (if you want to do arithmetics with them there is bignumber.js) You can use Douglas Crockford JSON.js library as a base for your parser. EDIT2 ( 7 years after original answer ) – it might soon be possible to solve … Read more
which factors influence performance of these operations? Probably the compiler and compiler version; but does the operating system or the CPU make/model influence this as well? Mostly the processor architecture (and model – please read model where I mention processor architecture in this section). The compiler may have some influence, but most compilers do pretty … Read more
Parsing string into int64 example: // Use the max value for signed 64 integer. http://golang.org/pkg/builtin/#int64 var s string = “9223372036854775807” i, err := strconv.ParseInt(s, 10, 64) if err != nil { panic(err) } fmt.Printf(“Hello, %v with type %s!\n”, i, reflect.TypeOf(i)) output: Hello, 9223372036854775807 with type int64! https://play.golang.org/p/XOKkE6WWer