Zip stored 0%, should I be concerned?
Do you run zip with recursion option? zip -r output.zip folder Without -r, the zip will not compress with sub-directories and lead to deflated 0%.
zip
How to create a zip file in the same format as the Finder’s “Compress” menu item?
I have a ruby script that makes iPhone App Store builds for me, but the zips it was generating wouldn’t get accepted by iTunes Connect. They were accepted if I used Finder’s “Compress” function. millenomi’s answer came close for me, but this command is what ended up working. iTunes Connect accepted my build, and the … Read more
Unzipping a file from InputStream and returning another InputStream
Concepts GZIPInputStream is for streams (or files) zipped as gzip (“.gz” extension). It doesn’t have any header information. This class implements a stream filter for reading compressed data in the GZIP file format If you have a real zip file, you have to use ZipFile to open the file, ask for the list of files … Read more
What is the best/easiest way to create ZIP archive in .NET?
I’ve always used SharpZipLib Forgot the why part: Mainly because its been around for a long time. It is well documented, and has an intuitive API. Plus it’s open source if you’re into that type of thing.
How to create a zip file using shell script?
From your question, I understand that you want to zip the files in the “Results” directory without considering the directory “Results” itself when trying to zip. If so, then use the below commands #!/bin/bash cd /home/admin/1/2/3/Results zip -r /home/admin/download.zip ./* After this, the zip file would be created in the required location. Zip file is … Read more
How to send zip files in the python Flask framework?
BytesIO() needs to be passed bytes data, but a ZipFile() object is not bytes-data; you actually created a file on your harddisk. You can create a ZipFile() in memory by using BytesIO() as the base: memory_file = BytesIO() with zipfile.ZipFile(memory_file, ‘w’) as zf: files = result[‘files’] for individualFile in files: data = zipfile.ZipInfo(individualFile[‘fileName’]) data.date_time = … Read more
How can I list the contents of a .zip folder in c#?
.NET 4.5 or newer finally has built-in capability to handle generic zip files with the System.IO.Compression.ZipArchive class (http://msdn.microsoft.com/en-us/library/system.io.compression.ziparchive%28v=vs.110%29.aspx) in assembly System.IO.Compression. No need for any 3rd party library. string zipPath = @”c:\example\start.zip”; using (ZipArchive archive = ZipFile.OpenRead(zipPath)) { foreach (ZipArchiveEntry entry in archive.Entries) { Console.WriteLine(entry.FullName); } }
getInputStream for a ZipEntry from ZipInputStream (without using the ZipFile class)
it works this way static InputStream getInputStream(File zip, String entry) throws IOException { ZipInputStream zin = new ZipInputStream(new FileInputStream(zip)); for (ZipEntry e; (e = zin.getNextEntry()) != null;) { if (e.getName().equals(entry)) { return zin; } } throw new EOFException(“Cannot find ” + entry); } public static void main(String[] args) throws Exception { InputStream in = getInputStream(new … Read more