Under Windows, you need the msvcrt module, specifically, it seems from the way you describe your problem, the function msvcrt.getch: Read a keypress and return the resulting character. Nothing is echoed to the console. This call will block if a keypress is not already available, but will not wait for Enter to be pressed. (etc … Read more
Figured it out. A combination of react-file-reader and HTML5’s FileReader (see this page). Placed the react-file-reader bit inside of render: <ReactFileReader handleFiles={this.handleFiles} fileTypes={‘.csv’}> <button className=”btn”>Upload</button> </ReactFileReader> And then this above. handleFiles = files => { var reader = new FileReader(); reader.onload = function(e) { // Use reader.result alert(reader.result) } reader.readAsText(files[0]); }
$Password is a Securestring, and this will return the plain text password. [Runtime.InteropServices.Marshal]::PtrToStringAuto([Runtime.InteropServices.Marshal]::SecureStringToBSTR($Password))
As Michael said, the issue is buffering. By default, output is buffered until you print a newline (or until the buffer is full if you have really long lines), so you’ll most often see this issue when trying to do same-line prompts using putStr like you’re doing. I suggest defining a small helper function like … Read more
is there even a limit?! Not intrinsically in Unicode. There is the concept of a ‘Stream-Safe’ format in UAX-15 that sets a limit of 30 combiners… Unicode strings in general are not guaranteed to be Stream-Safe, but this could certainly be taken as a sign that Unicode don’t intend to standardise new characters that would … Read more
EAFP try: x = float(a) except ValueError: print(“You must enter a number”)
You could read the entire input line from scanner, then split the line by , then you have a String[], parse each number into int[] with index one to one matching…(assuming valid input and no NumberFormatExceptions) like String line = scanner.nextLine(); String[] numberStrs = line.split(“,”); int[] numbers = new int[numberStrs.length]; for(int i = 0;i < … Read more
Python 3: inp = int(input(“Enter the inputs : “) or “42”) Python 2: inp = int(raw_input(“Enter the inputs : “) or “42”) How does it work? If nothing was entered then input/raw_input returns empty string. Empty string in Python is False, bool(“”) -> False. Operator or returns first truthy value, which in this case is … Read more
read-line is the correct function.. (println (read-line)) ..would basically echo the users input: Clojure 1.0.0- user=> (println (read-line)) this is my input this is my input To use it in an if statement, you’d probably use let: (let [yayinput (read-line)] (if (= yayinput “1234”) (println “Correct”) (println “Wrong”))) Hope that’s enough to get you started, … Read more