You could do this: String str = “…”; List<String> elephantList = Arrays.asList(str.split(“,”)); Basically the .split() method will split the string according to (in this case) delimiter you are passing and will return an array of strings. However, you seem to be after a List of Strings rather than an array, so the array must be … Read more
var numbers = sNumbers?.Split(‘,’)?.Select(Int32.Parse)?.ToList(); Recent versions of C# (v6+) allow you to do null checks in-line using the null-conditional operator
>> “1,2,3,4”.split(“,”) => [“1”, “2”, “3”, “4”] Or for integers: >> “1,2,3,4”.split(“,”).map { |s| s.to_i } => [1, 2, 3, 4] Or for later versions of ruby (>= 1.9 – as pointed out by Alex): >> “1,2,3,4”.split(“,”).map(&:to_i) => [1, 2, 3, 4]
If you’re using git add -p and even after splitting with s, you don’t have a small enough change, you can use e to edit the patch directly. This can be a little confusing, but if you carefully follow the instructions in the editor window that will be opened up after pressing e then you’ll … Read more
There’s a one-liner for everything. 🙂 var output = input.split(/[, ]+/).pop();
Press Control+w, then hit q to close each window at a time. Update: Also consider eckes answer which may be more useful to you, involving :on (read below) if you don’t want to do it one window at a time.
var str=”abcdefghijkl”; console.log(str.match(/.{1,3}/g)); Note: Use {1,3} instead of just {3} to include the remainder for string lengths that aren’t a multiple of 3, e.g: console.log(“abcd”.match(/.{1,3}/g)); // [“abc”, “d”] A couple more subtleties: If your string may contain newlines (which you want to count as a character rather than splitting the string), then the . won’t … Read more
You can do something like this: “1234567890”.match(/.{1,2}/g); // Results in: [“12”, “34”, “56”, “78”, “90”] The method will still work with strings whose size is not an exact multiple of the chunk-size: “123456789”.match(/.{1,2}/g); // Results in: [“12”, “34”, “56”, “78”, “9”] In general, for any string out of which you want to extract at-most n-sized … Read more
string[] tokens = str.Split(new[] { “is Marco and” }, StringSplitOptions.None); If you have a single character delimiter (like for instance ,), you can reduce that to (note the single quotes): string[] tokens = str.Split(‘,’);
You can use the DataFrame constructor with lists created by to_list: import pandas as pd d1 = {‘teams’: [[‘SF’, ‘NYG’],[‘SF’, ‘NYG’],[‘SF’, ‘NYG’], [‘SF’, ‘NYG’],[‘SF’, ‘NYG’],[‘SF’, ‘NYG’],[‘SF’, ‘NYG’]]} df2 = pd.DataFrame(d1) print (df2) teams 0 [SF, NYG] 1 [SF, NYG] 2 [SF, NYG] 3 [SF, NYG] 4 [SF, NYG] 5 [SF, NYG] 6 [SF, NYG] df2[[‘team1′,’team2’]] … Read more