You can create a custom encoder that returns a list when it encounters a set. Here’s an example: >>> import json >>> class SetEncoder(json.JSONEncoder): … def default(self, obj): … if isinstance(obj, set): … return list(obj) … return json.JSONEncoder.default(self, obj) … >>> json.dumps(set([1,2,3,4,5]), cls=SetEncoder) ‘[1, 2, 3, 4, 5]’ You can detect other types this way … Read more
A set is an unordered data structure, so it does not preserve the insertion order. This depends on your requirements. If you have an normal list, and want to remove some set of elements while preserving the order of the list, you can do this with a list comprehension: >>> a = [1, 2, 20, … Read more
:text will fail for a input with a type value of hidden. It’s also much more efficient to just use: $(“#texens”).val(“tinkumaster”); ID attributes should be unique on a web page, make sure yours are as this may contribute to any problems you’re having, and specifying a more complicated selector just slows things down and doesn’t … Read more
int size = myHashSet.size(); int item = new Random().nextInt(size); // In real life, the Random object should be rather more shared than this int i = 0; for(Object obj : myhashSet) { if (i == item) return obj; i++; }
List<String> list = new ArrayList<String>(listOfTopicAuthors);
You can use union method for sets: set.union(other_set) Note that it returns a new set i.e it doesn’t modify itself.
The Set interface does not provide any ordering guarantees. Its sub-interface SortedSet represents a set that is sorted according to some criterion. In Java 6, there are two standard containers that implement SortedSet. They are TreeSet and ConcurrentSkipListSet. In addition to the SortedSet interface, there is also the LinkedHashSet class. It remembers the order in … Read more
According to this thread: Indeed, CPython’s sets are implemented as something like dictionaries with dummy values (the keys being the members of the set), with some optimization(s) that exploit this lack of values So basically a set uses a hashtable as its underlying data structure. This explains the O(1) membership checking, since looking up an … Read more
A short-hand way to do it is to convert it to an array via the ES6 spread operator. Then all the array functions are available to you. const mySet = new Set([1,2,3,4]); […mySet].reduce(…);
Try this test2.removeAll(test1); Set#removeAll Removes from this set all of its elements that are contained in the specified collection (optional operation). If the specified collection is also a set, this operation effectively modifies this set so that its value is the asymmetric set difference of the two sets.