Yes! It really is more numerically stable. For the case that you’re looking at, the numbers [0.0, 0.1, …, 0.9], note that under round-ties-to-away, only four of those numbers are rounding down (0.1 through 0.4), five are rounded up, and one (0.0) is unchanged by the rounding operation, and then of course that pattern repeats … Read more
You can refer to the Largest Remainder Method used in election: Wikipedia: Largest Remainder Method In your case, you have USA: 42.857… Australia: 28.571… Germany: 28.571… If you take the integer part, you get USA: 42 Australia: 28 Germany: 28 which adds up to 98, and you want to take two more. Now, you look … Read more
To round a double up to 2 decimal places, you can use: #include <iostream> #include <cmath> int main() { double value = 0.123; value = std::ceil(value * 100.0) / 100.0; std::cout << value << std::endl; // prints 0.13 return 0; } To round up to n decimal places, you can use: double round_up(double value, int … Read more
The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example: >>> round(15768, -3) 16000 >>> round(1218, -3) 1000 So the short answer is: Call round with the second argument of -3 to round to the nearest 1000. A minor warning since … Read more
You’re dividing by an int, it wil give an int as result. (which makes 13 / 7 = 1) Try casting it to a floating point first: averagesDoubles = (sumInt / (double)ratingListBox.Items.Count); The averagesDoubles = Math.Round(averagesDoubles, 2); is reponsible for rounding the double value. It will round, 5.976 to 5.98, but this doesn’t affect the … Read more
Given you want to round down to the hour, you can simply replace microsecond, second and minute with zeros: print(datetime.now().replace(microsecond=0, second=0, minute=0)) If you want to round down to the previous hour (as stated in the example 2017-01-11 13:26:12.0 to 2017-01-11 12:00:00.0), replace microsecond, second and minute with zeros, then subtract one hour: from datetime … Read more
Use this code. Here is a working example http://plnkr.co/edit/xnN1HnJtTel6WA24GttR?p=preview {{num | currency:’USD’:true:’1.2-2′}} Explanation : number_expression | number[:digitInfo] Finally we get a decimal number as text. Find the description. number_expression: An angular expression that will give output a number. number : A pipe keyword that is used with pipe operator. digitInfo : It defines number format. … Read more
It looks like this was a long-standing bug in JDK 7 that was finally fixed. See for example: https://bugs.openjdk.java.net/browse/JDK-8029896 https://bugs.openjdk.java.net/browse/JDK-7131459 There is a draft plan to provide the following advisory with JDK 8 which explains the issue: ——————————————————————— Area: Core Libraries / java.text Synopsis: A wrong rounding behavior of JDK7 has been fixed. The rounding … Read more
Just use int(): x := float32(3.1) fmt.Println(int(x)) Which produces 3 as needed, without having to use string conversions or the like.
Another way is to use FIXED function, you can specify the number of decimal places but it defaults to 2 if the places aren’t specified, i.e. =FIXED(E5,2) or just =FIXED(E5)