You can use this function: function str_lreplace($search, $replace, $subject) { $pos = strrpos($subject, $search); if($pos !== false) { $subject = substr_replace($subject, $replace, $pos, strlen($search)); } return $subject; }
Build a new list with a list comprehension: new_items = [x if x % 2 else None for x in items] You can modify the original list in-place if you want, but it doesn’t actually save time: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] for index, item in enumerate(items): … Read more
You need a /g on there, like this: var textTitle = “this is a test”; var result = textTitle.replace(/ /g, ‘%20’); console.log(result); You can play with it here, the default .replace() behavior is to replace only the first match, the /g modifier (global) tells it to replace all occurrences.
Use abolish.vim: :%S/badjob/goodjob/g
Be aware, that \W leaves the underscore. A short equivalent for [^a-zA-Z0-9] would be [\W_] text.replace(/[\W_]+/g,” “); \W is the negation of shorthand \w for [A-Za-z0-9_] word characters (including the underscore) Example at regex101.com
At a very generic level UPDATE MyTable SET StringColumn = REPLACE (StringColumn, ‘SearchForThis’, ‘ReplaceWithThis’) WHERE SomeOtherColumn LIKE ‘%PATTERN%’ In your case you say these were escaped but since you don’t specify how they were escaped, let’s say they were escaped to GREATERTHAN UPDATE MyTable SET StringColumn = REPLACE (StringColumn, ‘GREATERTHAN’, ‘>’) WHERE articleItem LIKE ‘%GREATERTHAN%’ … Read more
Rust Regex in the Find/Replace in Files Sidebar Rob Lourens of MSFT wrote that the file search uses Rust regex. The Rust language documentation describes the syntax. JavaScript Regex in the Find/Replace in File Widget Alexandru Dima of MSFT wrote that the find widget uses JavaScript regex. As Wicktor commented, ECMAScript 5’s documentation describes the … Read more
.ix indexer works okay for pandas version prior to 0.20.0, but since pandas 0.20.0, the .ix indexer is deprecated, so you should avoid using it. Instead, you can use .loc or iloc indexers. You can solve this problem by: mask = df.my_channel > 20000 column_name=”my_channel” df.loc[mask, column_name] = 0 Or, in one line, df.loc[df.my_channel > … Read more
TLDR Use this method if you want the fastest regex-based solution. For a dataset similar to the OP’s, it’s approximately 1000 times faster than the accepted answer. If you don’t care about regex, use this set-based version, which is 2000 times faster than a regex union. Optimized Regex with Trie A simple Regex union approach … Read more
ciw (change inner word) will change the whole word under the cursor. Compare with cw which will only change the word from the current cursor position. For more info see this SO question/answer.