Here a first attempt at the top of my head. $configFiles = Get-ChildItem . *.config -rec foreach ($file in $configFiles) { (Get-Content $file.PSPath) | Foreach-Object { $_ -replace “Dev”, “Demo” } | Set-Content $file.PSPath }
You need to double escape any RegExp characters (once for the slash in the string and once for the regexp): “$TESTONE $TESTONE”.replace( new RegExp(“\\$TESTONE”,”gm”),”foo”) Otherwise, it looks for the end of the line and ‘TESTONE’ (which it never finds). Personally, I’m not a big fan of building regexp’s using strings for this reason. The level … Read more
You would use the replace method: text = text.replace(‘old’, ‘new’); The first argument is what you’re looking for, obviously. It can also accept regular expressions. Just remember that it does not change the original string. It only returns the new value.
You can use DataFrame.fillna or Series.fillna which will replace the Python object None, not the string ‘None’. import pandas as pd import numpy as np For dataframe: df = df.fillna(value=np.nan) For column or series: df.mycol.fillna(value=np.nan, inplace=True)
Search->File menu (also accessible using Ctrl+H, then navigate to File tab), enter the text to search for, hit the Replace… button which will give you another dialog where you can replace text.
Goto “Search”->”File” from menubar at the top left Enter text, file pattern and projects Click “Replace…” button at the bottom Enter new text click ok Voilà…
You need seek to the beginning of the file before writing and then use file.truncate() if you want to do inplace replace: import re myfile = “path/test.xml” with open(myfile, “r+”) as f: data = f.read() f.seek(0) f.write(re.sub(r”<string>ABC</string>(\s+)<string>(.*)</string>”, r”<xyz>ABC</xyz>\1<xyz>\2</xyz>”, data)) f.truncate() The other way is to read the file then open it again with open(myfile, ‘w’): … Read more
String target = “FOOBar”; target = target.replaceAll(“(?i)foo”, “”); System.out.println(target); Output: Bar It’s worth mentioning that replaceAll treats the first argument as a regex pattern, which can cause unexpected results. To solve this, also use Pattern.quote as suggested in the comments.
Use the replaceEach() method from Apache Commons StringUtils: StringUtils.replaceEach(story, new String[]{“foo”, “bar”}, new String[]{“bar”, “foo”})
For versions before Visual studio 2012: It works when I do this: find include “{[a-zA-Z]+\.h}”, replace with include <\1>. The most relevant parts for your question are the curly braces {} and the back reference \1: \n references to the n’th group indicated by curly braces in the search expression. For versions Visual studio 2012 … Read more