The JSON might contain a list of objects, which needs to be searched: Python 2.7 version: def item_generator(json_input, lookup_key): if isinstance(json_input, dict): for k, v in json_input.iteritems(): if k == lookup_key: yield v else: for child_val in item_generator(v, lookup_key): yield child_val elif isinstance(json_input, list): for item in json_input: for item_val in item_generator(item, lookup_key): yield item_val … Read more
grep -r REGEX . Replace . with whatever directory you want to search from.
In general, there is no way to determine the complexity of a given function Warning! Wall of text incoming! 1. There are very simple algorithms that no one knows whether they even halt or not. There is no algorithm that can decide whether a given program halts or not, if given a certain input. Calculating … Read more
You can do SelectMany List<Location> result = myLocationList.SelectMany(x => x.Children).ToList(); You can use where condition for some selective results like List<Location> result = myLocationList.Where(y => y.ParentID == someValue) .SelectMany(x => x.Children).ToList(); If you only required Id’s of Children you can do List<long> idResult = myLocationList.SelectMany(x => x.Children) .SelectMany(x => x.ID).ToList();
That question is like asking what’s the difference between a car and a DeLorean. In recursion function calls itself until reaches a base case. In backtracking you use recursion in order to explore all the possibilities until you get the best result for the problem. Can be a bit hard to understand, I attach some … Read more
Based on Aaron Brager and ullstrm answers Details Xcode 9.1, Swift 4, Xcode Version 10.3 (10G8), Swift 5 Solution extension UIView { class func getAllSubviews<T: UIView>(from parenView: UIView) -> [T] { return parenView.subviews.flatMap { subView -> [T] in var result = getAllSubviews(from: subView) as [T] if let view = subView as? T { result.append(view) } … Read more
If you really want your recursive directory deletion to follow through symbolic links, then I don’t think there is any platform independent way of doing so without keeping track of all the directories you have traversed. However, in pretty much every case I can think of you would just want to delete the actual symbolic … Read more
You use ‘and’: type firstType = | T1 of secondType and secondType = | T1 of firstType
I think the problem is here: for color in self.domains[var]: if not self._valid(var, color): continue self.map[var].color = color for key in node.neighbors: if color in self.domains[key]: self.domains[key].remove(color) # This is potentially bad. if key == var when self.domains[key].remove(color) is called, you change the size of the set you’re currently iterating over. You can avoid this … Read more
As you suspect, you’re returning the match of the first property seen. You should return false if that property doesn’t match, but keep looking otherwise. Also, return false if there’s no prop property found on y (that is, the counts match, but not the actual properties). If all properties have matched, return true: var deepEqual … Read more