Why is 199.96 – 0 = 200 in SQL?

I need to start by unwrapping this a bit so I can see what’s going on: SELECT 199.96 – ( 0.0 * FLOOR( CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)) ) ) Now let’s see exactly what types SQL Server is using for each side of the subtraction operation: SELECT SQL_VARIANT_PROPERTY (199.96 ,’BaseType’), SQL_VARIANT_PROPERTY … Read more

What range of numbers can be represented in a 16-, 32- and 64-bit IEEE-754 systems?

For a given IEEE-754 floating point number X, if 2^E <= abs(X) < 2^(E+1) then the distance from X to the next largest representable floating point number (epsilon) is: epsilon = 2^(E-52) % For a 64-bit float (double precision) epsilon = 2^(E-23) % For a 32-bit float (single precision) epsilon = 2^(E-10) % For a … Read more

Endless sine generation in C

Instead of calculating sine as a function of time, maintain a sine/cosine pair and advance it through complex number multiplication. This doesn’t require any trigonometric functions or lookup tables; only four multiplies and an occasional re-normalization: static const double a = 2 * M_PI * 280 * 30e-6; static const double dx = cos(a); static … Read more

PHP – Floating Number Precision [duplicate]

Because floating point arithmetic != real number arithmetic. An illustration of the difference due to imprecision is, for some floats a and b, (a+b)-b != a. This applies to any language using floats. Since floating point are binary numbers with finite precision, there’s a finite amount of representable numbers, which leads accuracy problems and surprises … Read more

How many double numbers are there between 0.0 and 1.0?

Java doubles are in IEEE-754 format, therefore they have a 52-bit fraction; between any two adjacent powers of two (inclusive of one and exclusive of the next one), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that’s the number of distinct doubles between 0.5 included and … Read more

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