How can val() return Number?
A text input’s value attribute will always return a string. You need to parseInt the value to get an integer: parseInt($(‘#myInput’).val(), 10);
A text input’s value attribute will always return a string. You need to parseInt the value to get an integer: parseInt($(‘#myInput’).val(), 10);
Giving you the complete answer would have no point at all since this is homework, so here are a few pointers : Even or Odd: number % 2 == 0 definitely is a very good way to find whether your number is even. In case you do not know %, this does modulo which is … Read more
Use the NumberFormatter class that are in php 😉 $f = new NumberFormatter(“en”, NumberFormatter::SPELLOUT); echo $f->format(1432); That would output “one thousand four hundred thirty-two”
Swift 3 & 4 extension String { var digits: String { return components(separatedBy: CharacterSet.decimalDigits.inverted) .joined() } } Swift 5 You should be able to omit return Also: Read the comment from @onmyway133 for a word of caution
Build bipartite graph structure – connect a[i] with all its divisors from b[]. Then find maximum matching and check whether it is perfect matching (number of edges in matching is equal to the number of pairs (if graph is directed) or to doubled number). Arbitrary chosen Kuhn algorithm implementation here. Upd: @Eric Duminil made great … Read more
Edit: This answer seems to be generating some confusion. The original question was asking how to convert scientific notation in the form of a string to a number (so that it could be used for calculation). However, a significant number of people finding this answer seem to think it’s about converting a number that is … Read more
Short answer: The toString() function takes the decimal, converts it to binary and adds a “-” sign. A zero fill right shift converts it’s operands to signed 32-bit integers in two complements format. A more detailed answer: Question 1: //If you try (-3).toString(2); //show “-11” It’s in the function .toString(). When you output a number … Read more
The expressions 0.0 and 00.0 are parsed differently. 0.0 is parsed as a numeric literal 1 00.0 is parsed as: 00 – octal numeric literal 2 . – property accessor 0 – identifier name Your code throws syntax error because 0 is not a valid JavaScript identifier. The following example works since toString is a … Read more
If you use LINQ to Objects and the list is long, I would use: List<int> list = new List<int> { 2, 5, 7, 10 }; int number = 9; int closest = list.Aggregate((x,y) => Math.Abs(x-number) < Math.Abs(y-number) ? x : y); This method is slightly more complex than the solution that Anthony Pegram suggested, but … Read more
This should work for all classes that extend Number, and are Comparable to themselves. By adding the & Comparable you allow to remove all the type checks and provides runtime type checks and error throwing for free when compared to Sarmun answer. class NumberComparator<T extends Number & Comparable> implements Comparator<T> { public int compare( T … Read more