Prevent negative inputs in form input type=”number”?

This uses Javascript, but you don’t have to write your own validation routine. Instead just check the validity.valid property. This will be true if and only if the input falls within the range. <html> <body> <form action=”#”> <input type=”number” name=”test” min=0 oninput=”validity.valid||(value=””);”><br> <input type=”submit” value=”Submit”> </form> </body> </html>

Convert Java Number to BigDecimal : best way

This is fine, remember that using the constructor of BigDecimal to declare a value can be dangerous when it’s not of type String. Consider the below… BigDecimal valDouble = new BigDecimal(0.35); System.out.println(valDouble); This will not print 0.35, it will infact be… 0.34999999999999997779553950749686919152736663818359375 I’d say your solution is probably the safest because of that.

Why does double in C print fewer decimal digits than C++?

With MinGW g++ (and gcc) 7.3.0 your results are reproduced exactly. This is a pretty weird case of Undefined Behavior. The Undefined Behavior is due to using printf without including an appropriate header, ¹violating the “shall” in C++17 §20.5.2.2 ” A translation unit shall include a header only outside of any declaration or definition, and … Read more

Get number of digits before decimal point

Solution without converting to string (which can be dangerous in case of exotic cultures): static int GetNumberOfDigits(decimal d) { decimal abs = Math.Abs(d); return abs < 1 ? 0 : (int)(Math.Log10(decimal.ToDouble(abs)) + 1); } Note, that this solution is valid for all decimal values UPDATE In fact this solution does not work with some big … Read more