@Paul Creasey had the simplest solution as the regex, but here it is as a simple jQuery plugin: $.fn.digits = function(){ return this.each(function(){ $(this).text( $(this).text().replace(/(\d)(?=(\d\d\d)+(?!\d))/g, “$1,”) ); }) } You could then use it like this: $(“span.numbers”).digits();
Here is a solution that works for any long value and that I find quite readable (the core logic is done in the bottom three lines of the format method). It leverages TreeMap to find the appropriate suffix. It is surprisingly more efficient than a previous solution I wrote that was using arrays and was … Read more
This is what you need: np.set_printoptions(suppress=True) Here is the documentation.
from decimal import Decimal ‘%.2E’ % Decimal(‘40800000000.00000000000000’) # returns ‘4.08E+10′ In your ‘40800000000.00000000000000’ there are many more significant zeros that have the same meaning as any other digit. That’s why you have to tell explicitly where you want to stop. If you want to remove all trailing zeros automatically, you can try: def format_e(n): a=”%E” … Read more
Using Java’s Float class. float f = Float.parseFloat(“25″); String s = Float.toString(25.0f); To compare it’s always better to convert the string to float and compare as two floats. This is because for one float number there are multiple string representations, which are different when compared as strings (e.g. “25” != “25.0” != “25.00” etc.)
Granted, the answer I linked in the comments is not very helpful. You can specify your own string converter like so. In [25]: pd.set_option(‘display.float_format’, lambda x: ‘%.3f’ % x) In [28]: Series(np.random.randn(3))*1000000000 Out[28]: 0 -757322420.605 1 -1436160588.997 2 -1235116117.064 dtype: float64 I’m not sure if that’s the preferred way to do this, but it works. … Read more
You can use: String.format(“%02d”, myNumber) See also the javadocs
This is a bit of a grey area. You need to recall that R will always invoke a print method, and these print methods listen to some options. Including ‘scipen’ — a penalty for scientific display. From help(options): ‘scipen’: integer. A penalty to be applied when deciding to print numeric values in fixed or exponential … Read more
You could use… Math.trunc() (truncate fractional part, also see below) Math.floor() (round down) Math.ceil() (round up) Math.round() (round to nearest integer) …dependent on how you wanted to remove the decimal. Math.trunc() isn’t supported on all platforms yet (namely IE), but you could easily use a polyfill in the meantime. Another method of truncating the fractional … Read more
Sorry for reactivating this question, but I didn’t find the right answer here. In formatting numbers you can use 0 as a mandatory place and # as an optional place. So: // just two decimal places String.Format(“{0:0.##}”, 123.4567); // “123.46” String.Format(“{0:0.##}”, 123.4); // “123.4” String.Format(“{0:0.##}”, 123.0); // “123” You can also combine 0 with #. … Read more