The type of a template parameter in a function can’t be deduced from a default argument. As shown in the example on cppreference.com: Type template parameter cannot be deduced from the type of a function default argument: template<typename T> void f(T = 5, T = 7); void g() { f(1); // OK: calls f<int>(1, 7) … Read more
No, Standard C does not support either. Why do you feel you need to convert your C++ code to C? That could get quite tricky – I’d have thought writing wrappers would be the way to go, if your C++ must be callable from C.
It’s exactly the same thing. No need to pick one instead of the other. Usually default keyword is handy when you have computer-generated code. It makes life easier to just use every single column in the insert clause and just use default when you don’t have a specific value for certain column. Other than that, … Read more
This will not change your font permanently, but it’s worth a try. matplotlib.rc(‘font’, family=’sans-serif’) matplotlib.rc(‘font’, serif=”Helvetica Neue”) matplotlib.rc(‘text’, usetex=’false’) matplotlib.rcParams.update({‘font.size’: 22})
What makes you think the object n points to should be deleted by default? The default destructor destroys the pointer, not what it’s pointing to. Edit: I’ll see if I can make this a little more clear. If you had a local pointer, and it went out of scope, would you expect the object it … Read more
Well yes. The default value of a nullable or other reference type is null while the default value for a long or other value type is 0 (and any other members set to their defaults). In this case: default(Nullable<long>) == null default(long?) == null default(long) == 0L