Can’t use modulus on doubles?
The % operator is for integers. You’re looking for the fmod() function. #include <cmath> int main() { double x = 6.3; double y = 2.0; double z = std::fmod(x,y); }
The % operator is for integers. You’re looking for the fmod() function. #include <cmath> int main() { double x = 6.3; double y = 2.0; double z = std::fmod(x,y); }
I always use my own mod function, defined as int mod(int x, int m) { return (x%m + m)%m; } Of course, if you’re bothered about having two calls to the modulus operation, you could write it as int mod(int x, int m) { int r = x%m; return r<0 ? r+m : r; } … Read more
Instead of the modulo operator, which has slightly different semantics, for non-negative integers, you can use the remainder operator %. For your exact example: if ((a % 2) == 0) { isEven = true; } else { isEven = false; } This can be simplified to a one-liner: isEven = (a % 2) == 0;
The % (modulo) operator yields the remainder from the division of the first argument by the second. The numeric arguments are first converted to a common type. A zero right argument raises the ZeroDivisionError exception. The arguments may be floating point numbers, e.g., 3.14%0.7 equals 0.34 (since 3.14 equals 4*0.7 + 0.34.) The modulo operator … Read more
C99 requires that when a/b is representable: (a/b) * b + a%b shall equal a This makes sense, logically. Right? Let’s see what this leads to: Example A. 5/(-3) is -1 => (-1) * (-3) + 5%(-3) = 5 This can only happen if 5%(-3) is 2. Example B. (-5)/3 is -1 => (-1) * … Read more
So rand() is a pseudo-random number generator which chooses a natural number between 0 and RAND_MAX, which is a constant defined in cstdlib (see this article for a general overview on rand()). Now what happens if you want to generate a random number between say 0 and 2? For the sake of explanation, let’s say … Read more
Number.prototype.mod = function (n) { “use strict”; return ((this % n) + n) % n; }; Taken from this article: The JavaScript Modulo Bug
Here’s an explanation in layman’s terms. Let’s assume you want to fill up a library with books and not just stuff them in there, but you want to be able to easily find them again when you need them. So, you decide that if the person that wants to read a book knows the title … Read more
For some number y and some divisor x compute the quotient (quotient)[1] and remainder (remainder) as: const quotient = Math.floor(y/x); const remainder = y % x; Example: const quotient = Math.floor(13/3); // => 4 => the times 3 fits into 13 const remainder = 13 % 3; // => 1 [1] The integer number resulting … Read more