Note: Originally I posted C# code in this answer for purposes of illustration, since C# allows you to pass int parameters by reference with the ref keyword. I’ve decided to update it with actual legal Java code using the first MutableInt class I found on Google to sort of approximate what ref does in C#. … Read more
Iterate your list in reverse with a for loop: for (int i = safePendingList.Count – 1; i >= 0; i–) { // some code // safePendingList.RemoveAt(i); } Example: var list = new List<int>(Enumerable.Range(1, 10)); for (int i = list.Count – 1; i >= 0; i–) { if (list[i] > 5) list.RemoveAt(i); } list.ForEach(i => Console.WriteLine(i)); … Read more
If you prefer a solution that does not require the initialization of the counter outside the loop, then you can compare the current iteration key against the function that tells you the last / first key of the array. PHP 7.3 and newer: foreach ($array as $key => $element) { if ($key === array_key_first($array)) { … Read more
For iterating on keys of Arrays, Strings, or Objects, use for .. in : for (let key in yourobject) { console.log(key, yourobject[key]); } With ES6, if you need both keys and values simultaneously, do for (let [key, value] of Object.entries(yourobject)) { console.log(key, value); } To avoid logging inherited properties, check with hasOwnProperty : for (let … Read more
var arr = [ {“id”:”10″, “class”: “child-of-9”}, {“id”:”11″, “class”: “child-of-10”}]; for (var i = 0; i < arr.length; i++){ document.write(“<br><br>array index: ” + i); var obj = arr[i]; for (var key in obj){ var value = obj[key]; document.write(“<br> – ” + key + “: ” + value); } } note: the for-in method is cool … Read more
Just like Perl, loop1: for (var i in set1) { loop2: for (var j in set2) { loop3: for (var k in set3) { break loop2; // breaks out of loop3 and loop2 } } } as defined in EMCA-262 section 12.12. [MDN Docs] Unlike C, these labels can only be used for continue and … Read more
The array is being re-indexed when you do a .splice(), which means you’ll skip over an index when one is removed, and your cached .length is obsolete. To fix it, you’d either need to decrement i after a .splice(), or simply iterate in reverse… var i = Auction.auctions.length while (i–) { … if (…) { … Read more
foreach($array as $key=>$value) { // do stuff } $key is the index of each $array element
def chunker(seq, size): return (seq[pos:pos + size] for pos in range(0, len(seq), size)) Works with any sequence: text = “I am a very, very helpful text” for group in chunker(text, 7): print(repr(group),) # ‘I am a ‘ ‘very, v’ ‘ery hel’ ‘pful te’ ‘xt’ print(‘|’.join(chunker(text, 10))) # I am a ver|y, very he|lpful text animals … Read more
To safely remove from a collection while iterating over it you should use an Iterator. For example: List<String> names = …. Iterator<String> i = names.iterator(); while (i.hasNext()) { String s = i.next(); // must be called before you can call i.remove() // Do something i.remove(); } From the Java Documentation : The iterators returned by … Read more