One line, faster than the for loop of the OP (although not the fastest) and very concise: num_lines = sum(1 for _ in open(‘myfile.txt’)) You can also boost the speed (and robustness) by using rbU mode and include it in a with block to close the file: with open(“myfile.txt”, “rbU”) as f: num_lines = sum(1 … Read more
Ignacio’s answer is correct, but might fail if you have a 32 bit process. But maybe it could be useful to read the file block-wise and then count the \n characters in each block. def blocks(files, size=65536): while True: b = files.read(size) if not b: break yield b with open(“file”, “r”) as f: print sum(bl.count(“\n”) … Read more
There’s always the “brute force”: Search->File Type the following in “Containing text” -> ^.*$. Then check the “Regular Expression” checkbox Type the following in “File name patterns” -> *.java Click “Search” Check the number of matches in the “Search” Tab.
You can run something like git ls-files | xargs wc -l Which will give you the total count → You can also add more instructions. Like just looking at the JavaScript files. git ls-files | grep ‘\.js’ | xargs wc -l Or use this handy little tool → https://line-count.herokuapp.com/
xargs will let you cat all the files together before passing them to wc, like you asked: git ls-files | xargs cat | wc -l But skipping the intermediate cat gives you more information and is probably better: git ls-files | xargs wc -l
One line, probably pretty fast: num_lines = sum(1 for line in open(‘myfile.txt’))