From Jacob, Heroku’s Director of Security at the time: The router doesn’t overwrite X-Forwarded-For, but it does guarantee that the real origin will always be the last item in the list. This means that, if you access a Heroku app in the normal way, you will just see your IP address in the X-Forwarded-For header: … Read more
I can find the IP address with hostname -i Of course, that may not be completely accurate if there is more than one interface. Edit Note: According to the hostname man page, hostname -i uses DNS to resolve the ip address, where hostname -I displays all the addresses except loopback, does not depend on DNS, … Read more
Take a look at IP Address Calculations with C# on MSDN blogs. It contains an extension method (IsInSameSubnet) that should meet your needs as well as some other goodies. public static class IPAddressExtensions { public static IPAddress GetBroadcastAddress(this IPAddress address, IPAddress subnetMask) { byte[] ipAdressBytes = address.GetAddressBytes(); byte[] subnetMaskBytes = subnetMask.GetAddressBytes(); if (ipAdressBytes.Length != subnetMaskBytes.Length) … Read more
As far as I can see there is no standard method for getting the remote address of your local machine. If you need the remote address for (testing) your geocoding, I suggest adding 127.0.0.1 to your database table that matches IP addresses with locations. As a last resort you could also hard code your remote … Read more
I’m assuming you want to match these ranges: 127. 0.0.0 – 127.255.255.255 127.0.0.0 /8 10. 0.0.0 – 10.255.255.255 10.0.0.0 /8 172. 16.0.0 – 172. 31.255.255 172.16.0.0 /12 192.168.0.0 – 192.168.255.255 192.168.0.0 /16 You are missing some dots that would cause it to accept for example 172.169.0.0 even though this should not be accepted. I’ve fixed … Read more
Try this: InetAddress address = InetAddress.getByName(new URL(urlString).getHost()); To get the raw IP: String ip = address.getHostAddress();
Use the netifaces module. Because networking is complex, using netifaces can be a little tricky, but here’s how to do what you want: >>> import netifaces >>> netifaces.interfaces() [‘lo’, ‘eth0’] >>> netifaces.ifaddresses(‘eth0’) {17: [{‘broadcast’: ‘ff:ff:ff:ff:ff:ff’, ‘addr’: ’00:11:2f:32:63:45′}], 2: [{‘broadcast’: ‘10.0.0.255’, ‘netmask’: ‘255.255.255.0’, ‘addr’: ‘10.0.0.2’}], 10: [{‘netmask’: ‘ffff:ffff:ffff:ffff::’, ‘addr’: ‘fe80::211:2fff:fe32:6345%eth0’}]} >>> for interface in netifaces.interfaces(): … … Read more
That’s Classless Inter-Doman Routing notation. The /24 means that the routing prefix of the subnet is 24 bits long, which means there’s ony 8 bits left for the subnet itself, i.e. 123.218.44.0 to 123.218.44.255
This is pretty easy: try { InetAddress localhost = InetAddress.getLocalHost(); LOG.info(” IP Addr: ” + localhost.getHostAddress()); // Just in case this host has multiple IP addresses…. InetAddress[] allMyIps = InetAddress.getAllByName(localhost.getCanonicalHostName()); if (allMyIps != null && allMyIps.length > 1) { LOG.info(” Full list of IP addresses:”); for (int i = 0; i < allMyIps.length; i++) { … Read more
This is one solution… public static IPEndPoint CreateIPEndPoint(string endPoint) { string[] ep = endPoint.Split(‘:’); if(ep.Length != 2) throw new FormatException(“Invalid endpoint format”); IPAddress ip; if(!IPAddress.TryParse(ep[0], out ip)) { throw new FormatException(“Invalid ip-adress”); } int port; if(!int.TryParse(ep[1], NumberStyles.None, NumberFormatInfo.CurrentInfo, out port)) { throw new FormatException(“Invalid port”); } return new IPEndPoint(ip, port); } Edit: Added a version … Read more