Isn’t the solution you are looking for just: require ‘socket’ addr_infos = Socket.ip_address_list Since a machine can have multiple interfaces and multiple IP Addresses, this method returns an array of Addrinfo. You can fetch the exact IP addresses like this: addr_infos.each do |addr_info| puts addr_info.ip_address end You can further filter the list by rejecting loopback … Read more
Documentation for socket() on Linux is split between various manpages including ip(7) that specifies that you have to use 0 or IPPROTO_UDP for UDP and 0 or IPPROTO_TCP for TCP. When you use 0, which happens to be the value of IPPROTO_IP, UDP is used for SOCK_DGRAM and TCP is used for SOCK_STREAM. In my … Read more
If you know which devices are out there you can use the Ping Class. This will allow you to at least fill up the ARP table. You can always execute ARP -a and parse the output if you have to. Here is also a link that shows how to pinvoke to call GetIpNetTable. I have … Read more
The answer is complicated. If your servlet is running on a webserver that is behind a reverse proxy or load balancer, then that web proxy can be configured to inject a request header that gives the IP address that the request came from. Different reverse proxies will inject different headers. Consult the documentation for your … Read more
You don’t have to set the IP, but you can reference the container’s virtual hostname, and this is the same value as you named your linked container. This means you can indeed set the DB_HOST from within the docker-compose.yml, either with links (recommended) or external_links: your_application: build: . ports: – “9180:80” – “9543:443” external_links: – … Read more
Even if there is already an accepted answer, the solution seems not to be valid. nginx has the log_format directive, which has a context of http. This means, the log_format can only be (valid) set within the http {} section of the config file, NOT within the server sections! On the other hand we have … Read more
Let’s write both in binary: 130.45.34.36 = 10000010.00101101.00100010.00100100 255.255.240.0 = 11111111.11111111.11110000.00000000 A bitwise AND between the two would give us the network address: 10000010.00101101.00100010.00100100 (ip address) AND 11111111.11111111.11110000.00000000 (subnet mask) = 10000010.00101101.00100000.00000000 = 130.45.32.0 (the resulting network address) A bitwise OR between the network address and the inverted subnet mask would give us the broadcast … Read more