Have a look at the ByteBuffer class. ByteBuffer b = ByteBuffer.allocate(4); //b.order(ByteOrder.BIG_ENDIAN); // optional, the initial order of a byte buffer is always BIG_ENDIAN. b.putInt(0xAABBCCDD); byte[] result = b.array(); Setting the byte order ensures that result[0] == 0xAA, result[1] == 0xBB, result[2] == 0xCC and result[3] == 0xDD. Or alternatively, you could do it manually: … Read more
Simple int(x) will work as well.
use std::stringstream unsigned int x; std::stringstream ss; ss << std::hex << “fffefffe”; ss >> x; the following example produces -65538 as its result: #include <sstream> #include <iostream> int main() { unsigned int x; std::stringstream ss; ss << std::hex << “fffefffe”; ss >> x; // output it as a signed type std::cout << static_cast<int>(x) << std::endl; … Read more
Literals that start with 0x are hexadecimal integers. (base 16) The number 0x6400 is 25600. 6 * 16^3 + 4 * 16^2 = 25600 For an example including letters (also used in hexadecimal notation where A = 10, B = 11 … F = 15) The number 0x6BF0 is 27632. 6 * 16^3 + 11 … Read more
int and long were “unified” a few versions back. Before that it was possible to overflow an int through math ops. 3.x has further advanced this by eliminating long altogether and only having int. Python 2: sys.maxint contains the maximum value a Python int can hold. On a 64-bit Python 2.7, the size is 24 … Read more
There are two ways to fix the problem which is caused by the last print statement. You can assign the result of the str(c) call to c as correctly shown by @jamylak and then concatenate all of the strings, or you can replace the last print simply with this: print “a + b as integers: … Read more
In C++11 you can use std::to_string: #include <string> std::string s = std::to_string(5); If you’re working with prior to C++11, you could use C++ streams: #include <sstream> int i = 5; std::string s; std::stringstream out; out << i; s = out.str(); Taken from http://notfaq.wordpress.com/2006/08/30/c-convert-int-to-string/
That is R’s way of printing a zero length vector (an integer one), so you could test for a being of length 0: R> length(a) [1] 0 It might be worth rethinking the strategy you are using to identify which elements you want, but without further specific details it is difficult to suggest an alternative … Read more
Well, the most efficient way, presuming you know the size of the integer, would be a lookup. Should be faster than the much shorter logarithm based approach. If you don’t care about counting the ‘-‘, remove the + 1. #include <climits> // generic solution template <class T> int numDigits(T number) { int digits = 0; … Read more
Use int() on a boolean test: x = int(x == ‘true’) int() turns the boolean into 1 or 0. Note that any value not equal to ‘true’ will result in 0 being returned.