The most simple solution is to use .split()to create a list of strings: x = x.split() Alternatively, you can use a list comprehension in combination with the .split() method: x = [int(i) for i in x.split()] You could even use map map as a third option: x = list(map(int, x.split())) This will create a list … Read more
You don’t need a whole function for this; a simple cast will suffice: int x; static_cast<char*>(static_cast<void*>(&x)); Any object in C++ can be reinterpreted as an array of bytes. If you want to actually make a copy of the bytes into a separate array, you can use std::copy: int x; char bytes[sizeof x]; std::copy(static_cast<const char*>(static_cast<const void*>(&x)), … Read more
They are the same type, as in C. No differences at all. Of course, unsigned can be used as a qualifier for other integral types. But by default, unsigned is the same as unsigned int.
You can create an int[] from any Collection<Integer> (including a HashSet<Integer>) using Java 8 streams: int[] array = coll.stream().mapToInt(Number::intValue).toArray(); The library is still iterating over the collection (or other stream source) on your behalf, of course. In addition to being concise and having no external library dependencies, streams also let you go parallel if you … Read more
Before Swift 3, many types were automatically “bridged” to an instance of some NSObject subclass where necessary, such as String to NSString, or Int, Float, … to NSNumber. As of Swift 3 you have to make that conversion explicit: var currentIndex = 0 for item in self.selectedFolder.arrayOfTasks { item.index = currentIndex as NSNumber // <– … Read more
The parseInt() function parses a string and returns an integer,10 is the Radix or Base [DOC] var number = parseInt(id.substring(indexPos) , 10 ) + 1;
string s = “1,5,7”; int[] nums = Array.ConvertAll(s.Split(‘,’), int.Parse); or, a LINQ-y version: int[] nums = s.Split(‘,’).Select(int.Parse).ToArray(); But the first one should be a teeny bit faster.
In C ‘a’ is an integer constant (!?!), so 4 is correct for your architecture. It is implicitly converted to char for the assignment. sizeof(char) is always 1 by definition. The standard doesn’t say what units 1 is, but it is often bytes.
You can implicitly convert between numerical types, even when that loses precision: char c = i; However, you might like to enable compiler warnings to avoid potentially lossy conversions like this. If you do, then use static_cast for the conversion. Of the other casts: dynamic_cast only works for pointers or references to polymorphic class types; … Read more
Use the .toInt method on Long, i.e. seconds.toInt