Long.decode(str) accepts a variety of formats: Accepts decimal, hexadecimal, and octal numbers given by the following grammar: DecodableString: Signopt DecimalNumeral Signopt 0x HexDigits Signopt 0X HexDigits Signopt # HexDigits Signopt 0 OctalDigits Sign: – But in your case that won’t help, your String is beyond the scope of what long can hold. You need a … Read more
As of Swift 2, all integer types have a constructor init?(_ text: String, radix: Int = default) so that both integer to hex string and hex string to integer conversions can be done with built-in methods. Example: let num = 1000 let str = String(num, radix: 16) print(str) // “3e8” if let num2 = Int(str, … Read more
I like to use this little piece of code to use HTML web colors in my apps. Usage: [self.view setBackgroundColor: [self colorWithHexString:@”FFFFFF”]]; /* white */ The Code: -(UIColor*)colorWithHexString:(NSString*)hex { NSString *cString = [[hex stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] uppercaseString]; // String should be 6 or 8 characters if ([cString length] < 6) return [UIColor grayColor]; // strip 0X … Read more
The width used in format is always a minimum width. In this case, instead of using sub string operations I would suggest: String.format(“%05X”, decInt & 0xFFFFF);
To address your actual question, this occurs if you’re trying to access the django server over https. Switch back to http and that error will disappear.
You can get a tuple of rgba values for the segment with index i by calling cmap(i). There is also already a function that turns rgb values into hex. As Joe Kington wrote in the comments, you can use matplotlib.colors.rgb2hex. Therefore, a possible solution would be: from pylab import * cmap = cm.get_cmap(‘seismic’, 5) # … Read more
Try: printf(“%04x”,a); 0 – Left-pads the number with zeroes (0) instead of spaces, where padding is specified. 4 (width) – Minimum number of characters to be printed. If the value to be printed is shorter than this number, the result is right justified within this width by padding on the left with the pad character. … Read more
The easiest way is to use Integer.toHexString(int)
Try this: hex_str = “0xAD4” hex_int = int(hex_str, 16) new_int = hex_int + 0x200 print hex(new_int) If you don’t like the 0x in the beginning, replace the last line with print hex(new_int)[2:]
In most cases, you want to parse more than one hex byte at once. In those cases, use the hex crate. parse this into an integer You want to use from_str_radix. It’s implemented on the integer types. use std::i64; fn main() { let z = i64::from_str_radix(“1f”, 16); println!(“{:?}”, z); } If your strings actually have … Read more