How do I join two paths in C#?
You have to use Path.Combine() as in the example below: string basePath = @”c:\temp”; string filePath = “test.txt”; string combinedPath = Path.Combine(basePath, filePath); // produces c:\temp\test.txt
You have to use Path.Combine() as in the example below: string basePath = @”c:\temp”; string filePath = “test.txt”; string combinedPath = Path.Combine(basePath, filePath); // produces c:\temp\test.txt
Quote from this link- If you want to find and print the top 10 largest files names (not directories) in a particular directory and its sub directories $ find . -type f -printf ‘%s %p\n’|sort -nr|head To restrict the search to the present directory use “-maxdepth 1” with find. $ find . -maxdepth 1 -printf … Read more
Use SysInternal’s RAMMap app. The Empty / Empty Standby List menu option will clear the Windows file cache.
To read only the first row of the csv file use next() on the reader object. with open(‘some.csv’, newline=””) as f: reader = csv.reader(f) row1 = next(reader) # gets the first line # now do something here # if first row is the header, then you can do one more next() to get the next … Read more
This is a way to see if any XML-files exists in that folder, yes. To check for specific files use File.Exists(path), which will return a boolean indicating wheter the file at path exists.
I didn’t think your question was very clear, but if all you need is a unique file name… import uuid unique_filename = str(uuid.uuid4())
You can use the File class to list the directories. File file = new File(“/path/to/directory”); String[] directories = file.list(new FilenameFilter() { @Override public boolean accept(File current, String name) { return new File(current, name).isDirectory(); } }); System.out.println(Arrays.toString(directories)); Update Comment from the author on this post wanted a faster way, great discussion here: How to retrieve a … Read more
In either case, I’d expect file.getParent() (or file.getParentFile()) to give you what you want. Additionally, if you want to find out whether the original File does exist and is a directory, then exists() and isDirectory() are what you’re after.
The simplest way is to read a character, and print it right after reading: int c; FILE *file; file = fopen(“test.txt”, “r”); if (file) { while ((c = getc(file)) != EOF) putchar(c); fclose(file); } c is int above, since EOF is a negative number, and a plain char may be unsigned. If you want to … Read more
As of Node v10, this is built into the fs.mkdir function, which we can use in combination with path.dirname: var fs = require(‘fs’); var getDirName = require(‘path’).dirname; function writeFile(path, contents, cb) { fs.mkdir(getDirName(path), { recursive: true}, function (err) { if (err) return cb(err); fs.writeFile(path, contents, cb); }); } For older versions, you can use mkdirp: … Read more