For the specific example you’ve given: dividing an (l,m,n) array by (m,) you can use np.newaxis: a = np.arange(1,61, dtype=float).reshape((3,4,5)) # Create a 3d array a.shape # (3,4,5) b = np.array([1.0, 2.0, 3.0, 4.0]) # Create a 1-d array b.shape # (4,) a / b # Gives a ValueError a / b[:, np.newaxis] # The … Read more
Surely you just need: double seconds = milliseconds / 1000.0; There’s no need to manually do the two parts separately – you just need floating point arithmetic, which the use of 1000.0 (as a double literal) forces. (I’m assuming your milliseconds value is an integer of some form.) Note that as usual with double, you … Read more
Python 3.x uses __truediv__ and __floordiv__. __div__ is 2.x-only.
C has div and ldiv. Whether these generate separate instructions for the quotient and remainder will depend on your particular standard library implementation and compiler and optimization settings. Starting with C99, you also have lldiv for larger numbers.
shell parsing is useful only for integer division: var1=8 var2=4 echo $((var1 / var2)) output: 2 instead your example: var1=3 var2=4 echo $((var1 / var2)) ouput: 0 it’s better to use bc: echo “scale=2 ; $var1 / $var2” | bc output: .75 scale is the precision required
In the bash shell, surround arithmetic expressions with $(( … )) $ echo $(( 7 / 3 )) 2 Although I think you are limited to integers.
int is an integer type; dividing two ints performs an integer division, i.e. the fractional part is truncated since it can’t be stored in the result type (also int!). Decimal, by contrast, has got a fractional part. By invoking Decimal.Divide, your int arguments get implicitly converted to Decimals. You can enforce non-integer division on int … Read more
Use modulus: // Will evaluate to true if the variable is divisible by 2 variable % 2 === 0
This is a simple function which performs the desired operation. But it requires the + operator, so all you have left to do is to add the values with bit-operators: // replaces the + operator int add(int x, int y) { while (x) { int t = (x & y) << 1; y ^= x; … Read more