I remember my CompSci professor saying never to use floats for currency. The reason for that is how the IEEE specification defines floats in binary format. Basically, it stores sign, fraction and exponent to represent a Float. It’s like a scientific notation for binary (something like +1.43*10^2). Because of that, it is impossible to store … Read more
You could use… Math.trunc() (truncate fractional part, also see below) Math.floor() (round down) Math.ceil() (round up) Math.round() (round to nearest integer) …dependent on how you wanted to remove the decimal. Math.trunc() isn’t supported on all platforms yet (namely IE), but you could easily use a polyfill in the meantime. Another method of truncating the fractional … Read more
Simplejson 2.1 and higher has native support for Decimal type: >>> json.dumps(Decimal(‘3.9’), use_decimal=True) ‘3.9’ Note that use_decimal is True by default: def dumps(obj, skipkeys=False, ensure_ascii=True, check_circular=True, allow_nan=True, cls=None, indent=None, separators=None, encoding=’utf-8′, default=None, use_decimal=True, namedtuple_as_object=True, tuple_as_array=True, bigint_as_string=False, sort_keys=False, item_sort_key=None, for_json=False, ignore_nan=False, **kw): So: >>> json.dumps(Decimal(‘3.9’)) ‘3.9’ Hopefully, this feature will be included in standard library.
Use 1, not 2. js> 2.3 % 1 0.2999999999999998
It means it’s a decimal literal, as others have said. However, the origins are probably not those suggested elsewhere in this answer. From the C# Annotated Standard (the ECMA version, not the MS version): The decimal suffix is M/m since D/d was already taken by double. Although it has been suggested that M stands for … Read more
Here’s some examples: decimal a = 1.994444M; Math.Round(a, 2); //returns 1.99 decimal b = 1.995555M; Math.Round(b, 2); //returns 2.00 You might also want to look at bankers rounding / round-to-even with the following overload: Math.Round(a, 2, MidpointRounding.ToEven); There’s more information on it here.
decimalVar.ToString(“#.##”); // returns “.5” when decimalVar == 0.5m or decimalVar.ToString(“0.##”); // returns “0.5” when decimalVar == 0.5m or decimalVar.ToString(“0.00”); // returns “0.50” when decimalVar == 0.5m
An explicit cast to double like this isn’t necessary: double trans = (double) trackBar1.Value / 5000.0; Identifying the constant as 5000.0 (or as 5000d) is sufficient: double trans = trackBar1.Value / 5000.0; double trans = trackBar1.Value / 5000d;
For money, always decimal. It’s why it was created. If numbers must add up correctly or balance, use decimal. This includes any financial storage or calculations, scores, or other numbers that people might do by hand. If the exact value of numbers is not important, use double for speed. This includes graphics, physics or other … Read more
Use setRoundingMode, set the RoundingMode explicitly to handle your issue with the half-even round, then use the format pattern for your required output. Example: DecimalFormat df = new DecimalFormat(“#.####”); df.setRoundingMode(RoundingMode.CEILING); for (Number n : Arrays.asList(12, 123.12345, 0.23, 0.1, 2341234.212431324)) { Double d = n.doubleValue(); System.out.println(df.format(d)); } gives the output: 12 123.1235 0.23 0.1 2341234.2125 EDIT: … Read more