This is a CLR restriction. Only primitive constants or arrays of primitives can be used as attribute parameters. The reason why is that an attribute must be encoded entirely in metadata. This is different than a method body which is coded in IL. Using MetaData only severely restricts the scope of values that can be … Read more
If you have Python 2.6 or newer, use format: ‘{0:.3g}’.format(num) For Python 2.5 or older: ‘%.3g’%(num) Explanation: {0}tells format to print the first argument — in this case, num. Everything after the colon (:) specifies the format_spec. .3 sets the precision to 3. g removes insignificant zeros. See http://en.wikipedia.org/wiki/Printf#fprintf For example: tests=[(1.00, ‘1’), (1.2, ‘1.2’), … Read more
What you want is %.2f, not 2%f. Also, you might want to replace your %d with a %f 😉 #include <cstdio> int main() { printf(“When this number: %f is assigned to 2 dp, it will be: %.2f “, 94.9456, 94.9456); return 0; } This will output: When this number: 94.945600 is assigned to 2 dp, … Read more
This link does a good job of explaining what you are looking for. Here is what is says: All these three Types, can be specified by the following Parameters (size, d). Where size is the total size of the String, and d represents precision. E.g To store a Number like 1234.567, you will set the … Read more
DATEDIFF(hour, start_date, end_date) will give you the number of hour boundaries crossed between start_date and end_date. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600.0 The documentation for DATEDIFF is available on MSDN: http://msdn.microsoft.com/en-us/library/ms189794%28SQL.105%29.aspx
If you use double or float, you should use rounding or expect to see some rounding errors. If you can’t do this, use BigDecimal. The problem you have is that 0.1 is not an exact representation, and by performing the calculation twice, you are compounding that error. However, 100 can be represented accurately, so try: … Read more
std::bitset has a .to_string() method that returns a std::string holding a text representation in binary, with leading-zero padding. Choose the width of the bitset as needed for your data, e.g. std::bitset<32> to get 32-character strings from 32-bit integers. #include <iostream> #include <bitset> int main() { std::string binary = std::bitset<8>(128).to_string(); //to binary std::cout<<binary<<“\n”; unsigned long decimal … Read more
By the way guys, (int)Decimal.MaxValue will overflow. You can’t get the “int” part of a decimal because the decimal is too friggen big to put in the int box. Just checked… its even too big for a long (Int64). If you want the bit of a Decimal value to the LEFT of the dot, you … Read more
A decimal(9,6) stores 6 digits on the right side of the comma. Whether to display trailing zeroes or not is a formatting decision, usually implemented on the client side. But since SSMS formats float without trailing zeros, you can remove trailing zeroes by casting the decimal to a float: select cast(123.4567 as DECIMAL(9,6)) , cast(cast(123.4567 … Read more
You have two options: Use float.as_integer_ratio(): >>> (0.25).as_integer_ratio() (1, 4) (as of Python 3.6, you can do the same with a decimal.Decimal() object.) Use the fractions.Fraction() type: >>> from fractions import Fraction >>> Fraction(0.25) Fraction(1, 4) The latter has a very helpful str() conversion: >>> str(Fraction(0.25)) ‘1/4’ >>> print Fraction(0.25) 1/4 Because floating point values … Read more