I’ve been working with Ruby and Rails for over 2 years and I’m just about a month into learning Scala and Lift, so my opinion is probably biased, but here it is. Ruby makes you feel amazing. Every new thing I discovered about the language made me giggle like a little schoolgirl. Working with gems … Read more
It sounds like you want a binary delta or perhaps an index derived from the application of a binary delta (like it’s size). You could then compare this index to some baseline that you determine experimentally to decide if it’s a “clone” or not. There are a lot of similarities between compression and delta creation, … Read more
It’s required to satisfy the verifiability constraints for the generated IL. Note that unverifiable doesn’t necessarily mean incorrect. It works just fine without the box instruction as long as its security context allows running unverifiable code. Verification is conservative and is based on a fixed rule set (like reachability). To simplify things, they chose not … Read more
It should be the same, but it is not guaranteed, because it depends on implementation details of the type T. Explanation: Without a constraint to T, o1.Equals(o2) will call Object.Equals, even if T implements IEquatable<T>. EqualityComparer<T>.Default however, will use Object.Equals only, if T doesn’t implement IEquatable<T>. If it does implement that interface, it uses IEquatable<T>.Equals. … Read more
For Swift 5 see rustylepord’s answer. Update for Swift 3: let letters = CharacterSet.letters let digits = CharacterSet.decimalDigits var letterCount = 0 var digitCount = 0 for uni in phrase.unicodeScalars { if letters.contains(uni) { letterCount += 1 } else if digits.contains(uni) { digitCount += 1 } } (Previous answer for older Swift versions) A possible … Read more
Typically this is accomplished by finding the Longest Common Subsequence (commonly called the LCS problem). This is how tools like diff work. Of course, diff is a line-oriented tool, and it sounds like your needs are somewhat different. However, I’m assuming that you’ve already constructed some way to compare words and sentences.
Yes, it’s valid – it will promote the int to a double before performing the comparison. See JLS section 15.20.1 (Numerical Comparison Operators) which links to JLS section 5.6.2 (Binary Numeric Promotion). From the latter: Widening primitive conversion (ยง5.1.2) is applied to convert either or both operands as specified by the following rules: If either … Read more
At first glance, it appears that x should always equal y, because two sets constructed from the same elements are always equal: >>> x = set([1, “a”, “b”, “c”, “z”, “f”]) >>> y = set([“a”, “b”, “c”, “z”, “f”, 1]) >>> x {1, ‘z’, ‘a’, ‘b’, ‘c’, ‘f’} >>> y {1, ‘z’, ‘a’, ‘b’, ‘c’, … Read more
The = “operator” in Prolog is actually a predicate (with infix notation) =/2 that succeeds when the two terms are unified. Thus X = 2 or 2 = X amount to the same thing, a goal to unify X with 2. The == “operator” differs in that it succeeds only if the two terms are … Read more
The explanation is in the comments in the code. Java has double values for both 0.0 and -0.0, as well as “not a number” (NaN). You can’t use simple == operator for these values. Take a peek into the doubleToLongBits() source and at the Javadoc for the Double.equals() method: Note that in most cases, for … Read more