This behaviour is defined in the C# specification (ECMA-334) in section 14.2.7 (I have highlighted the relevant part): For the relational operators < > <= >= a lifted form of an operator exists if the operand types are both non-nullable value types and if the result type is bool. The lifted form is constructed by … Read more
” == ‘0’ // false The left hand side is an empty string, and the right hand side is a string with one character. They are false because it is making a comparison between two un identical strings (thanks Niall). 0 == ” // true Hence, why this one is true, because 0 is falsy … Read more
It has to do with operator precedence in Python (the interpreter thinks you’re comparing True to not, since == has a higher precedence than not). You need some parentheses to clarify the order of operations: True == (not False) In general, you can’t use not on the right side of a comparison without parentheses. However, … Read more
I suggest that you read the excellent When is a Type not a Type? blog post by Brad Wilson. To summarize: a runtime type (represented by the internal type RuntimeType), managed by the CLR, is not always the same as a Type, which can be extended. Equals will check the underlying system type, whereas == … Read more
That particular aspect is a simple form of rewriting, reversing the operands. The primary operators == and <=> can be reversed, the secondaries !=, <, >, <=, and >=, can be rewritten in terms of the primaries. The reversing aspect can be illustrated with a relatively simple example. If you don’t have a specific B::operator==(A) … Read more
Two String objects will always be unequal to each other. Note that JavaScript has string primitive values as well as a String constructor to create wrapper objects. All object equality comparisons (especially with ===) are carried out as a test for reference equality. References to two different objects will of course never be equal to … Read more
In C++20 the way that the relational operators work was changed, notably with the introduction of the spaceship <=> operator. In particular, If you only provide operator==, then a != b is rewritten to !(a == b). From [over.match.oper]/3.4: The rewritten candidate set is determined as follows: For the relational ([expr.rel]) operators, the rewritten candidates … Read more
You should use CASE clause: CASE WHEN FieldA > FieldB THEN 1 ELSE 0 END AS [BIT]
$a === $b (Identical) TRUE if $a is equal to $b, and they are of the same type. (introduced in PHP 4) PHP Docs