Remember, you don’t have to tie yourself in knots with bit shifting if you’re not too familiar with the details. You can use a ByteBuffer to help you out: ByteBuffer bb = ByteBuffer.allocate(2); bb.order(ByteOrder.LITTLE_ENDIAN); bb.put(firstByte); bb.put(secondByte); short shortVal = bb.getShort(0); And vice versa, you can put a short, then pull out bytes. By the way, … Read more
No, there is no built-in method to do that. But, directly copied from HERE (with two fixes applied to the original code): /** * Knuth-Morris-Pratt Algorithm for Pattern Matching */ class KMPMatch { /** * Finds the first occurrence of the pattern in the text. */ public static int indexOf(byte[] data, byte[] pattern) { if … Read more
For (at least) Python 3.7 According to the docs: bytes objects are immutable sequences of single bytes bytearray objects are a mutable counterpart to bytes objects. And that’s pretty much it as far as bytes vs bytearray. In fact, they’re fairly interchangeable and designed to flexible enough to be mixed in operations without throwing errors. … Read more
It feels wasteful to create a string for each character just to Join them. Here’s one that is a little less wasteful, but with more boiler plate. playground://XEckr_rpr8 type sortRunes []rune func (s sortRunes) Less(i, j int) bool { return s[i] < s[j] } func (s sortRunes) Swap(i, j int) { s[i], s[j] = s[j], … Read more
byte[] response = new System.Net.WebClient().DownloadData(url);
Get the bytes of the string: obj.toString().getBytes(theCharset);
There are two problems: Int is a 64-bit integer on 64-bit platforms, your input data has only 32-bit. Int uses a little-endian representation on all current Swift platforms, your input is big-endian. That being said the following would work: let array : [UInt8] = [0, 0, 0, 0x0E] var value : UInt32 = 0 let … Read more
I’m not familiar with either of these books, but the second is closer to current reality. The first may be discussing a specific processor. Processors have been made with quite a variety of word sizes, not always a multiple of 8. The 8086 and 8087 processors used 16 bit words, and it’s likely this is … Read more
As I am on Kotlin 1.3 you may also be interested in the UByte soon (note that it’s an experimental feature. See also Kotlin 1.3M1 and 1.3M2 announcement) E.g.: @ExperimentalUnsignedTypes // just to make it clear that the experimental unsigned types are used fun ByteArray.toHexString() = asUByteArray().joinToString(“”) { it.toString(16).padStart(2, ‘0’) } The formatting option is … Read more
import ‘dart:convert’; String foo = ‘Hello world’; List<int> bytes = utf8.encode(foo); print(bytes); Output: [72, 101, 108, 108, 111, 32, 119, 111, 114, 108, 100] Also, if you want to convert back: String bar = utf8.decode(bytes);