byte[] bytes = ….; ByteArrayOutputStream baos = new ByteArrayOutputStream(bytes.length); baos.write(bytes, 0, bytes.length); Method description: Writes len bytes from the specified byte array starting at offset off to this byte array output stream.
System.out.println(Integer.toHexString(test[0])); OR (pretty print) System.out.printf(“0x%02X”, test[0]); OR (pretty print) System.out.println(String.format(“0x%02X”, test[0]));
You can use Arrays.copyOfRange() for that.
You are perhaps misunderstanding things. byte is very much intended for “accessing memory”. You are intended to use the type when the storage is just a sequence of bytes rather than an array of characters. Iostream types cannot be specialized with byte, since they’re designed around characters as their interface. That is, they do not … Read more
in python 3: >>> a=b’\x00\x00\x00\x00\x07\x80\x00\x03′ >>> b = list(a) >>> b [0, 0, 0, 0, 7, 128, 0, 3] >>> c = bytes(b) >>> c b’\x00\x00\x00\x00\x07\x80\x00\x03′ >>>
To read one byte: file.read(1) 8 bits is one byte.
byte is a 1-byte type so can vary between -128…127, so condition i < 128 is always true. When you add 1 to 127 it overflows and becomes -128 and so on in a (infinite) loop…
You’d have to write your own implementation of Iterable<Boolean> which took an array of bytes, and then created Iterator<Boolean> values which remembered the current index into the byte array and the current index within the current byte. Then a utility method like this would come in handy: private static Boolean isBitSet(byte b, int bit) { … Read more
Try this: private BufferedImage createImageFromBytes(byte[] imageData) { ByteArrayInputStream bais = new ByteArrayInputStream(imageData); try { return ImageIO.read(bais); } catch (IOException e) { throw new RuntimeException(e); } }
Supposing data is a char*. Working example using std::hex: for(int i=0; i<data_length; ++i) std::cout << std::hex << (int)data[i]; Or if you want to keep it all in a string: std::stringstream ss; for(int i=0; i<data_length; ++i) ss << std::hex << (int)data[i]; std::string mystr = ss.str();