Any good boolean expression simplifiers out there? [closed]
You can try Wolfram Alpha as in this example based on your input: http://www.wolframalpha.com/input/?i=((A%20OR%20B)%20AND%20(NOT%20B%20AND%20C)%20OR%20C)&t=crmtb01&f=rc
You can try Wolfram Alpha as in this example based on your input: http://www.wolframalpha.com/input/?i=((A%20OR%20B)%20AND%20(NOT%20B%20AND%20C)%20OR%20C)&t=crmtb01&f=rc
Those are the bitwise AND and bitwise OR operators. int a = 6; // 110 int b = 4; // 100 // Bitwise AND int c = a & b; // 110 // & 100 // —– // 100 // Bitwise OR int d = a | b; // 110 // | 100 // —– … Read more
Since nobody has broached the subject of why these are useful: I use bitwise operations a lot when working with flags. For example, if you want to pass a series of flags to an operation (say, File.Open(), with Read mode and Write mode both enabled), you could pass them as a single value. This is … Read more
They are almost synonymous, but not quite. The difference is that ! has a higher precedence than not, much like && and || are of higher precedence than and and or. ! has the highest precedence of all operators, and not one of the lowest, you can find the full table at the Ruby docs. … Read more
You can flip a value like so: myVal = !myVal; so your code would shorten down to: switch(wParam) { case VK_F11: flipVal = !flipVal; break; case VK_F12: otherVal = !otherVal; break; default: break; }
Your first step in these kinds of problems is always to make a logic table. A | B | Result ——————- T | T | do action C T | F | … F | T | do action C F | F | do action C Once you’ve made the table, the solution is … Read more
I suggest writing the code in a manner that indicates what you mean. If you want 3 values to be true, it seems natural to me that the value 3 appears somewhere. For instance, in C++: if ((int)a + (int)b + (int)c + (int)d == 3) … This is well defined in C++: the standard … Read more
As you can see, the AND operator drops every row in which at least one value equals -1. On the other hand, the OR operator requires both values to be equal to -1 to drop them. That’s right. Remember that you’re writing the condition in terms of what you want to keep, not in terms … Read more
To invert a boolean Series, use ~s: In [7]: s = pd.Series([True, True, False, True]) In [8]: ~s Out[8]: 0 False 1 False 2 True 3 False dtype: bool Using Python2.7, NumPy 1.8.0, Pandas 0.13.1: In [119]: s = pd.Series([True, True, False, True]*10000) In [10]: %timeit np.invert(s) 10000 loops, best of 3: 91.8 µs per … Read more
Order of operations causes (0 < 5 < 3) to be interpreted in javascript as ((0 < 5) < 3) which produces (true < 3) and true is counted as 1, causing it to return true. This is also why (0 < 5 < 1) returns false, (0 < 5) returns true, which is interpreted … Read more