Put it outside: SELECT COALESCE( ( SELECT SUM(i.Logged) FROM tbl_Sites s INNER JOIN tbl_Incidents i ON s.Location = i.Location WHERE s.Sites = @SiteName AND i.[month] = DATEADD(mm, DATEDIFF(mm, 0, GetDate()) -1,0) GROUP BY s.Sites ), 0) AS LoggedIncidents If you are returning multiple rows, change INNER JOIN to LEFT JOIN SELECT COALESCE(SUM(i.Logged),0) FROM tbl_Sites s … Read more
‘%03.1f’ works (1 could be any number, or empty string): >>> “%06.2f”%3.3 ‘003.30’ >>> “%04.f”%3.2 ‘0003’ Note that the field width includes the decimal and fractional digits.
BigDecimal ‘equals’ compares the value and the scale. If you only want to compare values (0 == 0.0) you should use compareTo: BigDecimal.ZERO.compareTo(BigDecimal.valueOf(0.0)) == 0 //true BigDecimal.ZERO.compareTo(BigDecimal.valueOf(0)) == 0 //true See the javadoc. As for the Double comparison, as explained by other answers, you are comparing a Double with an Integer in new Double(0.0).equals(0), which … Read more
Check out −0 (number) in Wikipedia Basically IEEE does actually define a negative zero. And by this definition for all purposes: -0.0 == +0.0 == 0 I agree with aaronasterling that -0.0 and +0.0 are different objects. Making them equal (equality operator) makes sure that subtle bugs are not introduced in the code. Think of … Read more
Check if the denominator is zero before dividing. This avoids the overhead of catching the exception, which may be more efficient if you expect to be dividing by zero a lot. def weird_division(n, d): return n / d if d else 0
A leading 0 indicates an octal number in JavaScript. An octal number cannot contain an 8; therefore, that number is invalid. Moreover, JSON doesn’t (officially) support octal numbers, so formally the JSON is invalid, even if the number would not contain an 8. Some parsers do support it though, which may lead to some confusion. … Read more
I’m assuming you mean the null pointer. It is guaranteed to compare equal to 0.1 But it doesn’t have to be represented with all-zero bits.2 See also the comp.lang.c FAQ on null pointers. See C99, 6.3.2.3. There’s no explicit claim; but see the footnote for C99, 7.20.3 (thanks to @birryree in the comments).
You should use DecimalFormat(“0.#”) For 4.3000 Double price = 4.3000; DecimalFormat format = new DecimalFormat(“0.#”); System.out.println(format.format(price)); output is: 4.3 In case of 5.000 we have Double price = 5.000; DecimalFormat format = new DecimalFormat(“0.#”); System.out.println(format.format(price)); And the output is: 5
-0 is (generally) treated as 0 *******. It can result when a negative floating-point number is so close to zero that it can be considered 0 (to be clear, I’m referring to arithmetic underflow, and the results of the following computations are interpreted as being exactly ±0, not just really small numbers). e.g. System.out.println(-1 / … Read more
Yes, divide by it. 1 / +0.0f is +Infinity, but 1 / -0.0f is -Infinity. It’s easy to find out which one it is with a simple comparison, so you get: if (1 / x > 0) // +0 here else // -0 here (this assumes that x can only be one of the two … Read more