is there any library that can give me XPATH for all the nodes in HTML page Yes, if this HTML page is a well-formed XML document. Depending on what you understand by “node”… //* selects all the elements in the document. /descendant-or-self::node() selects all elements, text nodes, processing instructions, comment nodes, and the root node … Read more
Here is a very simple way to do conditional processing using the full power of XSLT pattern matching and exclusively “push” style, and this even avoids the need to use conditional instructions such as <xsl:if> or <xsl:choose>: <xsl:stylesheet version=”1.0″ xmlns:xsl=”http://www.w3.org/1999/XSL/Transform”> <xsl:output omit-xml-declaration=”yes” indent=”yes”/> <xsl:template match=”/root/diagram[graph[1]/@color]”> Graph[1] has color </xsl:template> <xsl:template match=”/root/diagram[not(graph[1]/@color)]”> Graph[1] has not color … Read more
In XSLT, call system-property(‘xsl:version’). It will return 1.0 or 2.0 depending on whether you are using a 1.0 or 2.0 processor. In XPath, there’s no direct equivalent. But a quick test is to call current-date() with no arguments. If this succeeds, you have a 2.0 processor, if it fails, you have a 1.0 processor. Unless … Read more
from lxml import etree print(etree.tostring(root, pretty_print=True)) you may see more examples here: http://lxml.de/tutorial.html
You get the table like this: //span[@data-id=’table1′]/table Select the data-id attribute and get the child element of name table.
I am trying to write an xpath expression that selects all div tags that have an attribute id that start with CompanyCalendar. The following expression is perhaps what you are looking for: //div[starts-with(@id,’CompanyCalendar’)] What it does, in plain English, is Return all div elements in the XML document that have an attribute id whose attribute … Read more
When namespaces are used, these must be used in the XPath query also. Your XPath query would only work against elements with no namespace (as can be verified by removing the namespace from your XML). Here’s an example showing how you create and pass a namespace manager: var xml = … XML from your post … Read more
Use the following expression: //span[contains(concat(‘ ‘, @class, ‘ ‘), ‘ amount ‘)] You could use contains on its own, but that would also match classes like someamount. Test the above expression on the following input: <root> <span class=”test amount blah”/> <span class=”amount test”/> <span class=”test amount”/> <span class=”amount”/> <span class=”someamount”/> </root> It will select the … Read more
Try adding this code inside the loop at the top; Node singleNode = nodes.item(i); singleNode.getParentNode().removeChild(singleNode); then run each evaluation using the singleNode variable instead of nodes.item(i); (of course you change the name) Doing this detaches the node you are working with from the large main document. This will speed up the evaluate methods processing time … Read more