xml

Is there an XSLT buddy available somewhere?

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XSLT IDEs (Interactive Development Environments): XSelerator (the one I’ve been using for 6-7 years). Free, has a Debugger for MSXML, has intellisense for both XSLT 1.0 and XSLT 2.0. In addition has some dynamic intellisense. The debugger has breakpoints, data breakpoints,visualizes temporary trees, variables, test conditions, current output, …, etc. VS2008 — a good XML … Read more

invalid byte 2 of 2-byte UTF-8 sequence

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Most commonly it’s due to feeding ISO-8859-x (Latin-x, like Latin-1) but parser thinking it is getting UTF-8. Certain sequences of Latin-1 characters (two consecutive characters with accents or umlauts) form something that is invalid as UTF-8, and specifically such that based on first byte, second byte has unexpected high-order bits. This can easily occur when … Read more

How to rename XML attribute that generated after serializing List of objects

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The most reliable way is to declare an outermost DTO class: [XmlRoot(“myOuterElement”)] public class MyOuterMessage { [XmlElement(“item”)] public List<TestObject> Items {get;set;} } and serialize that (i.e. put your list into another object). You can avoid a wrapper class, but I wouldn’t: class Program { static void Main() { XmlSerializer ser = new XmlSerializer(typeof(List<Foo>), new XmlRootAttribute(“Flibble”)); … Read more

How do I detect XML parsing errors when using Javascript’s DOMParser in a cross-browser way?

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This is the best solution I’ve come up with. I attempt to parse a string that is intentionally invalid XML and observe the namespace of the resulting <parsererror> element. Then, when parsing actual XML, I can use getElementsByTagNameNS to detect the same kind of <parsererror> element and throw a Javascript Error. // My function that … Read more

How do I use a default namespace in an lxml xpath query?

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Something like this should work: import lxml.etree as et ns = {“atom”: “http://www.w3.org/2005/Atom”} tree = et.fromstring(xml) for node in tree.xpath(‘//atom:entry’, namespaces=ns): print node See also http://lxml.de/xpathxslt.html#namespaces-and-prefixes. Alternative: for node in tree.xpath(“//*[local-name() = ‘entry’]”): print node