More terminology (C, not C++): a prototype for a function declares the types of its arguments. Otherwise the function does not have a prototype. void f(); // Declaration, but not a prototype void f(void); // Declaration and prototype void f(int a, int b, float c); // Declaration and prototype Declarations that aren’t prototypes are holdovers … Read more
The difference is that some browsers allow you to overwrite the value of undefined. However, void anything always returns real undefined. undefined = 1; console.log(!!undefined); //true console.log(!!void 0); //false
void() is a function type (it’s a function which takes no arguments and returns nothing), so it’s not a valid type in sizeof().
Implicit Unit return type: def f() {println(“ABC”)} Explicit Unit return type: def g(): Unit = {println(“ABC”)} Return type inferred from the last method expression, still Unit because this is the type of println, but confusing: def h() = println(“ABC”) All the methods above are equivalent. I would prefer f() because the lack of = operator … Read more
It’s an interesting question. Since java enforces a return type (void is a return type) your first statement seems to make sense. I would take this only for convention. Since void is a placeholder and not an object, it was probably decided to leave it out for language coherency or compiler simplicity. From JLS A … Read more
You should use the getattr wrapper instead of directly retrieving the value of id. a = getattr(myobject, ‘id’, None) This is like saying “I would like to retrieve the attribute id from the object myobject, but if there is no attribute id inside the object myobject, then return None instead.” But it does it efficiently. … Read more
Edit: A new separate RFC for a void return type has been published, has passed the vote, and was implemented in PHP 7.1. There is now a void return type in PHP. 🙂 Original Post: Taken from wiki.php.net: Future Work Ideas for future work which are out of the scope of this RFC include: Allow … Read more
It for example happens in this case here: void initializeJSP(unknownType Experiment); Try using std::string instead of just string (and include the <string> header). C++ Standard library classes are within the namespace std::.
It also contains Void.TYPE, useful for testing return type with reflection: public void foo() {} … if (getClass().getMethod(“foo”).getReturnType() == Void.TYPE) …
In C++, there is no difference. In C, the difference is questionable. Some love to argue that the latter version (the one without void) is technically just a common implementation extension and not guaranteed to work by the standard because of the wording in the standard. However, the standard clearly states that in a function … Read more