AFAIK there is no way to do it with the standard Chrome PDF Viewer. Take a look at their support page https://support.google.com/chrome/answer/1060734. You could try requesting this feature but keep in mind that the PDF viewer is part of Chrome, not Chromium.
{{request.GET.param1}} in the template. (Using RequestContext) request.GET.get(‘param1’, None) in the view.
You don’t need to do this at all. The request is available in the template context automatically (as long as you enable the request context processor and use a RequestContext) – or you can just pass the request object directly in the context. And request.GET is a dictionary-like object, so once you have the request … Read more
When a URL is like domain/search/?q=haha, you would use request.GET.get(‘q’, ”). q is the parameter you want, and ” is the default value if q isn’t found. However, if you are instead just configuring your URLconf**, then your captures from the regex are passed to the function as arguments (or named arguments). Such as: (r’^user/(?P<username>\w{0,50})/$’, … Read more
I would use buildAndExpand from UriComponentsBuilder to pass all types of URI parameters. For example: String url = “http://test.com/solarSystem/planets/{planet}/moons/{moon}”; // URI (URL) parameters Map<String, String> urlParams = new HashMap<>(); urlParams.put(“planet”, “Mars”); urlParams.put(“moon”, “Phobos”); // Query parameters UriComponentsBuilder builder = UriComponentsBuilder.fromUriString(url) // Add query parameter .queryParam(“firstName”, “Mark”) .queryParam(“lastName”, “Watney”); System.out.println(builder.buildAndExpand(urlParams).toUri()); /** * Console output: * http://test.com/solarSystem/planets/Mars/moons/Phobos?firstName=Mark&lastName=Watney … Read more
Use forName static method of Charset class: byte[] postData = urlParameters.getBytes(Charset.forName(“UTF-8”)); List of standard charsets you can find in documentation.
Wow… I was not aware of that, see example: >>> urlparse.urlparse(“http://some.page.pl/nothing.py;someparam=some;otherparam=other?query1=val1&query2=val2#frag”) ParseResult(scheme=”http”, netloc=”some.page.pl”, path=”/nothing.py”, params=”someparam=some;otherparam=other”, query=’query1=val1&query2=val2′, fragment=”frag”) And help(urlparse.urlparse): Help on function urlparse in module urlparse: urlparse(url, scheme=””, allow_fragments=True) Parse a URL into 6 components: <scheme>://<netloc>/<path>;<params>?<query>#<fragment> Return a 6-tuple: (scheme, netloc, path, params, query, fragment). Note that we don’t break the components up in smaller … Read more
Yes it is true that decodeURIComponent function doesn’t convert + to space. So you have to replace the + using replace function. Ideally the below solution works. var str_name=”This+is+a+message+with+spaces”; decodeURIComponent((str_name + ”).replace(/\+/g, ‘%20’));
When you put the username and password in front of the host, this data is not sent that way to the server. It is instead transformed to a request header depending on the authentication schema used. Most of the time this is going to be Basic Auth which I describe below. A similar (but significantly … Read more