You can store country-power pairs into a Dictionary<string, int> then just get the score of a particular country by using indexer: var points = new Dictionary<string,int>(); // populate the dictionary… var usa = points[“USA”]; Edit: As suggested in comments you should store the information in external file, for example an xml would be a good … Read more
Because the scope is delimited by { and } and you have the a variable twice. You can avoid this compilation error by: switch(x) { case 1: { int a = 1; break; } case 2: { int a = 2; break; } } Note that in your example the compiler fails to succeed, because … Read more
That’s fine. The point is that the end of a case block should be unreachable – which it is here, because you’ve returned. Why are you returning new string(new char[0]) rather than just “” or string.Empty though? If you’re trying to make sure it’s a different string each time, you’ll actually run into a very … Read more
They are pretty similar but each has a few special features. switch switch is usually more compact than lots of nested if else and therefore, more readable If you omit the break between two switch cases, you can fall through to the next case in many C-like languages. With if else you’d need a goto … Read more
Neither. it uses the lookupswitch JVM instruction, which is essentially a table lookup. Take a look at the bytecode of the following example: public static void main(String… args) { switch (1) { case 1: break; case 2: break; } } public static void main(java.lang.String[]); Code: Stack=1, Locals=1, Args_size=1 0: iconst_1 1: lookupswitch{ //2 1: 28; … Read more
Maybe yield a Consumer of Event, so you yield something useful, the trade off is one more line for consumer.accept. Consumer<Event> consumer = switch (event.getEventType()) { case ORDER -> e -> handle((OrderEvent) e); case INVOICE -> e -> handle((InvoiceEvent) e); case PAYMENT -> e -> handle((PaymentEvent) e); }; consumer.accept(event); Continue if you concern performance Based … Read more
A switch compares the variable with a set of compile-time constants. Other than null, I can’t see any valid compile time constants that you might compare a pointer with. For example: switch (ptr) { case &var1: printf (“Pointing to var1”); break; case &var2: printf (“Pointing to var2”); break; } var1 and var2 are likely different … Read more
The version with int r = x + y; won’t compile either. The problem is that it is possible for r to come to scope without its initializer being executed. The code would compile fine if you removed the initializer completely (i.e. the line would read int r;). The best thing you can do is … Read more
You execute everything starting from the selected case up until you see a break or the switch statement ends. So it might be that only C is executed, or B and then C, or A and B and C, but never A and C
In bash, you can use the arithmetic expression: ((…)) if ((461<=X && X<=660)) then echo “480p” elif ((661<=X && X<=890)) then echo “720p” elif ((891<=X && X<=1200)) then echo “1080p” else echo “DVD” fi >> moviefinal