Note that since Kotlin 1.6 readLine()!! should be replaced with readln(). Here are A+B examples in Kotlin reading from stdin: fun main() { val (a, b) = readLine()!!.split(‘ ‘) println(a.toInt() + b.toInt()) } or fun main(vararg args: String) { val (a, b) = readLine()!!.split(‘ ‘).map(String::toInt) println(a + b) } or fun readInts() = readLine()!!.split(‘ ‘).map … Read more
File descriptors 0, 1 and 2 are for stdin, stdout and stderr respectively. File descriptors 3, 4, .. 9 are for additional files. In order to use them, you need to open them first. For example: exec 3<> /tmp/foo #open fd 3. echo “test” >&3 exec 3>&- #close fd 3. For more information take a … Read more
The program will not work properly because at Line 1, when the user presses Enter, it will leave in the input buffer 2 character: Enter key (ASCII code 13) and \n (ASCII code 10). Therefore, at Line 2, it will read the \n and will not wait for the user to enter a character. The … Read more
Passing a value to standard input in Bash is as simple as: your-command <<< “$your_variable” Always make sure you put quotes around variable expressions! Be cautious, that this will probably work only in bash and will not work in sh.
They are two different APIs that allow you to access the same stream of data blocks. The ‘readable’ API was introduced in Node 0.10.0 as part of “Streams 2”, so if you search for that, it should help. The core of the issue is that the ‘readable’ interface allows for much simpler managing and buffering … Read more
Python 3 does not expect ASCII from sys.stdin. It’ll open stdin in text mode and make an educated guess as to what encoding is used. That guess may come down to ASCII, but that is not a given. See the sys.stdin documentation on how the codec is selected. Like other file objects opened in text … Read more
Try wrapping *in* in a java.io.BufferedReader. And also use doseq instead of doall, as devstopfix pointed out: (doseq [ln (line-seq (java.io.BufferedReader. *in*))] (println ln)) Note that line-seq is documented to require a BufferedReader as its source.
It’s a little tricky to write a function which can read standard input, but works properly when no standard input is given. If you simply try to read from standard input, it will block until it receives any, much like if you simply type cat at the prompt. In bash 4, you can work around … Read more
You should add “throws IOException” to your main method: public static void main(String[] args) throws IOException { You can read a bit more about checked exceptions (which are specific to Java) in JLS.
here a concatenation solution: #include <stdio.h> #include <stdlib.h> #include <string.h> #define BUFFERSIZE 10 int main() { char *text = calloc(1,1), buffer[BUFFERSIZE]; printf(“Enter a message: \n”); while( fgets(buffer, BUFFERSIZE , stdin) ) /* break with ^D or ^Z */ { text = realloc( text, strlen(text)+1+strlen(buffer) ); if( !text ) … /* error handling */ strcat( text, … Read more