I am trying to write an xpath expression that selects all div tags that have an attribute id that start with CompanyCalendar. The following expression is perhaps what you are looking for: //div[starts-with(@id,’CompanyCalendar’)] What it does, in plain English, is Return all div elements in the XML document that have an attribute id whose attribute … Read more
Use generator expressions, the best way I think. for line in (line for line in x if not line.startswith(‘?’)): DO_STUFF Or your way: for line in x: if line.startswith(“?”): continue DO_STUFF Or: for line in x: if not line.startswith(“?”): DO_STUFF It is really up to your programming style. I prefer the first one, but maybe … Read more
Like this: aString.toUpperCase().startsWith(“SOMETHING”); aString.toUpperCase().endsWith(“SOMETHING”);
Some of the performance difference can be explained by taking into account the time it takes the . operator to do its thing: >>> x = ‘foobar’ >>> y = ‘foo’ >>> sw = x.startswith >>> %timeit x.startswith(y) 1000000 loops, best of 3: 316 ns per loop >>> %timeit sw(y) 1000000 loops, best of 3: … Read more
As already mentioned in the comments, if you use s.__contains__(“XYZ”) you get a result that is more similar to s.startswith(“XYZ”) because it needs to take the same route: Member lookup on the string object, followed by a function call. This is usually somewhat expensive (not enough that you should worry about of course). On the … Read more
$Group is an object, but you will actually need to check if $Group.samaccountname.StartsWith(“string”). Change $Group.StartsWith(“S_G_”) to $Group.samaccountname.StartsWith(“S_G_”).
You need a whole input match here. System.out.println(test.matches(“^(http|https|ftp)://.*$”)); Edit:(Based on @davidchambers’s comment) System.out.println(test.matches(“^(https?|ftp)://.*$”));
You could use a regular expression as follows: In [33]: bool(re.match(‘he’, ‘Hello’, re.I)) Out[33]: True In [34]: bool(re.match(‘el’, ‘Hello’, re.I)) Out[34]: False On a 2000-character string this is about 20x times faster than lower(): In [38]: s=”A” * 2000 In [39]: %timeit s.lower().startswith(‘he’) 10000 loops, best of 3: 41.3 us per loop In [40]: %timeit … Read more
As added to base in 3.3.0, startsWith (and endsWith) are exactly this. > startsWith(“what”, “wha”) [1] TRUE > startsWith(“what”, “ha”) [1] FALSE https://stat.ethz.ch/R-manual/R-devel/library/base/html/startsWith.html
Yes – because it does begin with the empty string. Indeed, the empty string logically occurs between every pair of characters. Put it this way: what definition of “starts with” could you give that would preclude this? Here’s a simple definition of “starts with” that doesn’t: “x starts with y if the first y.Length characters … Read more