I’ve separated this answer into two(2) methods. The first method will separate your fullname field into first, middle, and last names. The middle name will show as NULL if there is no middle name. SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ‘ ‘, 1), ‘ ‘, -1) AS first_name, If( length(fullname) – length(replace(fullname, ‘ ‘, ”))>1, SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ‘ ‘, 2), … Read more
The Natural Language Toolkit (nltk.org) has what you need. This group posting indicates this does it: import nltk.data tokenizer = nltk.data.load(‘tokenizers/punkt/english.pickle’) fp = open(“test.txt”) data = fp.read() print ‘\n—–\n’.join(tokenizer.tokenize(data)) (I haven’t tried it!)
str.split complements str.join, so “/”.join([”, ‘segment’, ‘segment’, ”]) gets you back the original string. If the empty strings were not there, the first and last “https://stackoverflow.com/” would be missing after the join().
Actually I found the way to do that. Suppose the two windows are number 1 and 2. Use join-pane -s 2 -t 1 This will move the 2nd window as a pane to the 1st window. The opposite command is break-pane
Try List<string> parts = line.Split(‘;’).Select(p => p.Trim()).ToList(); FYI, the Foreach method takes an Action (takes T and returns void) for parameter, and your lambda return a string as string.Trim return a string Foreach extension method is meant to modify the state of objects within the collection. As string are immutable, this would have no effect … Read more
You could use lastIndexOf() method on String String last = string.substring(string.lastIndexOf(‘-‘) + 1);
They’re essentially horses for courses. Scanner is designed for cases where you need to parse a string, pulling out data of different types. It’s very flexible, but arguably doesn’t give you the simplest API for simply getting an array of strings delimited by a particular expression. String.split() and Pattern.split() give you an easy syntax for … Read more
Two steps, for example, package main import ( “fmt” “strings” ) func main() { s := strings.Split(“127.0.0.1:5432”, “:”) ip, port := s[0], s[1] fmt.Println(ip, port) } Output: 127.0.0.1 5432 One step, for example, package main import ( “fmt” “net” ) func main() { host, port, err := net.SplitHostPort(“127.0.0.1:5432”) fmt.Println(host, port, err) } Output: 127.0.0.1 5432 … Read more
Using split() Snippet : var data =$(‘#date’).text(); var arr = data.split(“https://stackoverflow.com/”); $(“#date”).html(“<span>”+arr[0] + “</span></br>” + arr[1]+”https://stackoverflow.com/”+arr[2]); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <div id=”date”>23/05/2013</div> Fiddle When you split this string —> 23/05/2013 on / var myString = “23/05/2013”; var arr = myString.split(“https://stackoverflow.com/”); you’ll get an array of size 3 arr[0] –> 23 arr[1] –> 05 arr[2] –> 2013
Just use the split function. It returns a list, so you can keep the first element: >>> s1.split(‘:’) [‘Username’, ‘ How are you today?’] >>> s1.split(‘:’)[0] ‘Username’